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loris [4]
3 years ago
10

Which value of k will make this relationship NOT a function? {(−7, 2), (−1, 0), (4, 8), (k, 0)} ​

Mathematics
1 answer:
ruslelena [56]3 years ago
4 0

Answer:

In this example, if k = -7, this relationship is not a function, since x = -7 would have both y = 2 and y = 0.

Step-by-step explanation:

Requirement to be a function:

For a relationship to be a function, all values of x must have only one corresponding value of y.

In this question:

For x = -7, y = 2

For x = -1, y = 0

For x = 4, y = 0

For x = k, y = 0

A value of x must not have more than 1 value of y.

In this example, if k = -7, this relationship is not a function, since x = -7 would have both y = 2 and y = 0.

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For this case we have to define root properties:

\sqrt [n] {a ^ n} = a ^ {\frac {n} {n}} = a

In addition, we know that:

a ^ {- 1} = \frac {1} {a ^ 1} = \frac {1} {a}

On the other hand:

4 ^ 2 = 16

Thus, we can rewrite the given expression as:

\sqrt {4 ^ 2 * a ^ 8 * \frac {1} {b ^ 2}} =\\4 ^ {\frac {2} {2}} * a ^ {\frac {8} {2}} * \frac {1} {b ^ {\frac {2} {2}}} =\\4 * a ^ 4 * \frac {1} {b}

ANswer:

Option B

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Step-by-step explanation:

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PLZ HELP TEST IS BEING TIMED!!! What are the slope and the y-intercept of the linear function that is represented by the equatio
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Answer:

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Step-by-step explanation:

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