Question

Can some one explain how to do this?

Answer 1

Answer:

see explanation

Step-by-step explanation:

Using the tangent and sine ratios in the right triangle EFG

tan60° = $\frac{opposite}{adjacent}$ = $\frac{FG}{EG}$ = $\frac{28}{EG}$ ( multiply both sides by EG )

EG × tan60° = 28 ( divide both sides by tan60° )

EG = $\frac{28}{tan60}$ ≈ 16.2 in ( to the nearest tenth )

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sin60° = $\frac{opposite}{hypotenuse}$ = $\frac{FG}{EF}$ = $\frac{28}{EF}$ ( multiply both sides by EF )

EF × sin60° = 28 ( divide both sides by sin60° )

EF = $\frac{28}{sin60}$ ≈ 32.3 in ( to the nearest tenth )