Answer:
Explanation:
In this case, we have a <u>Friedel-Craft reaction</u> (see figure 1). Usually in this type of reaction, the benzene ring is <u>bonded directly to the carbon that has the halide atom</u>. But in this specific case, this is not happening.
To understand why we have to remember the reaction mechanism of this reaction. As first, step the Cl-C bond attacks the 
and we form a new bond between the alkyl halide and the , finally the C-Cl bond is broken and a <u>carbocation is formed</u>. In this case, we will have a primary carbocation, a very <u>unstable species</u>. Therefore we will have a <u>methyl shift</u> to obtain a tertiary carbocation.
This tertiary carbocation will react with and continues the reaction. (See figure 2)
I hope it helps!
Answer:
(a) 17,178 mg/m3
(b) 11,625 mg/m3
Explanation:
The concentration of CO in mg/m3 can be calculated as
For standard conditions (1 atm and 25°C), P/RT is 0.0409.
Concentration of 1.5% percent by volume of CO is equivalent to 1.5*10,000 ppm= 15,000 ppm CO.
The molecular weigth of CO is 28 g/mol.
(1) For 25°C and 1 atm conditions
(b) For 200°C and 1.1 atm,
Then the concentration in mg/m3 is
Answer:
Because boys are overrated
Explanation:
The very common mineral shown in the figure that is referred in this problem that is commonly a pink- to cream-colored mineral with wavy, light-colored lines and does not effervesce would be feldspar. It make up about 41 percent weight of the Earth's crust. It is a group of rocks that contains tectosilicate compounds.
Should be 33. but I habe no clue
