1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Olegator [25]
3 years ago
12

URGENT!! I will have brainliest!!!

Chemistry
1 answer:
Vlad [161]3 years ago
3 0

Answer:

sorry idk

Explanation:

You might be interested in
According to Arrhenius, NH4+ an acid or a base? Write an equation to support
sergejj [24]

According to Arrhenius definition of acids, NH4^+ is an acid.

According  to Arrhenius  definition of acids and bases, acid is any substance that produces hydrogen ion in solution as its only positive ion.

Following this definition, let us now consider what happens when NH4^+ is introduced into a water;

NH4^+(aq)-------> NH3(aq) + H^+(aq)

Hence, according to Arrhenius definition of acids, NH4^+ is an acid.

For another example of Arrhenius acids, see

brainly.com/question/516295

8 0
3 years ago
The half-life of cesium-137 is 30 years. Suppose we have a 180 mg sample. Find the mass that remains after t years. Let y(t) be
Stels [109]

Explanation:

1) Initial mass of the Cesium-137=N_o= 180 mg

Mass of Cesium after time t = N

Formula used :

N=N_o\times e^{-\lambda t}\\\\\lambda =\frac{0.693}{t_{\frac{1}{2}}}

Half life of the cesium-137 = t_{1/2}=30 years[p/tex]where,
[tex]N_o = initial mass of isotope

N = mass of the parent isotope left after the time, (t)

t_{\frac{1}{2}} = half life of the isotope

\lambda = rate constant

N=N_o\times e^{-(\frac{0.693}{t_{1/2}})\times t}

Now put all the given values in this formula, we get

N=180mg\times e^{-\frac{0.693}{30 years}\times t}

Mass that remains after t years.

N=180 mg\times e^{0.0231 year^{-1}\times t}

Therefore, the parent isotope remain after one half life will be, 100 grams.

2)

t = 70 years

N_o=180 mg

t_{1/2}= 30 yeras

N=180mg\times e^{-\frac{0.693}{30 years}\times 70 years}

N = 35.73 mg

35.73 mg of cesium-137 will remain after 70 years.

3)

N_o=180 mg

t_{1/2}= 30 yeras

N = 1 mg

t = ?

1 mg =180mg\times e^{-\frac{0.693}{30 years}\times t}

\frac{-30 year}{0.693}\times \ln \frac{1 mg}{180 mg}=t

t = 224.80 years ≈ 225 years

After 225 years only 1 mg of cesium-137 will remain.

7 0
3 years ago
Give two examples of energy transfer by conduction between two<br> objects
algol13
A boat being accelerated by the engine

Bringing water to the boil in an electric kettle
7 0
3 years ago
Which pictures shows the proper structure of the water molecule? Click the picture to see each choice.
Yuliya22 [10]

The third picture is the answer

Explanation:

there are 2 hydrogen atom 1 oxygen

7 0
2 years ago
Which statement about the orinoco river is true.
WITCHER [35]
Hello,

I think the answer is B) It is second longest river in south america 

Hope this helps!!

~Girlygir101~
3 0
4 years ago
Other questions:
  • What is the difference between mass and weight in detail?
    6·1 answer
  • Questions About Organizing The Elements
    7·1 answer
  • List the numbers of each atom in all the formulas above: H C
    12·2 answers
  • What would the percentage of thorium-232 (parent compound) be in a rock that was dated at 2.8 billions years?
    9·1 answer
  • The number of electrons in an oxide ion O^2- is?
    7·1 answer
  • Copper will NOT easily form a new substance when in contact with which of the following? moist air nitric acid sulfuric acid car
    13·2 answers
  • A Transverse Wave is what
    10·1 answer
  • 385 x 42.13 x 0.079 is (consider significant figures):
    10·1 answer
  • Un compuesto químico se puede representar gráficamente por medio de una
    13·1 answer
  • What happens to the electropositive character of elements on moving from left to right along a period in a periodic table?​
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!