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Ipatiy [6.2K]
3 years ago
10

Please help me out! i have a few more of these questions, about 4

Mathematics
2 answers:
Ne4ueva [31]3 years ago
6 0

Answer:

Step-by-step explanation:

put a point in at negative 1 first; that is the y value.

Then, go up 1 then to the right six points. that should result in the next point being at (0,6).

Keep going and draw a line

Eva8 [605]3 years ago
5 0

Step-by-step explanation:

You can make a table of values to find the points that belong to the line and then draw the line through those points. Here are some: (-6, -2), (0, -1), and (6, 5). You can use any value for x in your table. Hope this helps!

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Can someone check my work?. 1. Simplify the given expression.. (7 − 3i) • (2 − i) . 4 + i (MY ANSWER) . . 14 + 3i . . 11 − 13i .
Annette [7]
1. (7 − 3i) • (2 − i)
It is simplified as follows:
14 - 7i  -6i - 3
11 - 13i

2. <span>(−5 + 3i) • (1 − 2i) 
</span><span>It is simplified as follows:
</span><span>-5 + 10i + 3i + 6
1 + 13i

3. (1 + 3i) + (2 − 5i) 
</span><span>It is simplified as follows:
</span>1 + 3i + 2 − 5i<span>
3 - 2i

4. (6 + 2i) − (8 − 3i) 
</span><span>It is simplified as follows:
</span><span>6 + 2i − 8 + 3i
</span>-2 + 5i
4 0
3 years ago
Four time the sum of five and ten is what
frozen [14]
The answer is sixty!
4(5+10)
4(15)
60
3 0
3 years ago
Read 2 more answers
Evaluate the expression when b=5 and x = -7.<br> -b+7x
svlad2 [7]

Answer:

-54

Step-by-step explanation:

Substitute the numbers for the variables.

-(5)+7(-7)

=-5-49

=-54

6 0
3 years ago
Read 2 more answers
How can i differentiate this equation?
Dmitry_Shevchenko [17]

\bf y=\cfrac{2x^2-10x}{\sqrt{x}}\implies y=\cfrac{2x^2-10x}{x^{\frac{1}{2}}} \\\\\\ \cfrac{dy}{dx}=\stackrel{\textit{quotient rule}}{\cfrac{(4x-10)(\sqrt{x})~~-~~(2x^2-10x)\left( \frac{1}{2}x^{-\frac{1}{2}} \right)}{\left( x^{\frac{1}{2}} \right)^2}} \\\\\\ \cfrac{dy}{dx}=\cfrac{(4x-10)(\sqrt{x})~~-~~(2x^2-10x)\left( \frac{1}{2\sqrt{x}} \right)}{\left( x^{\frac{1}{2}} \right)^2} \\\\\\ \cfrac{dy}{dx}=\cfrac{(4x-10)(\sqrt{x})~~-~~\left( \frac{2x^2-10x}{2\sqrt{x}} \right)}{x}


\bf\cfrac{dy}{dx}=\cfrac{(4x-10)(\sqrt{x})~~-~~\left( \frac{2x^2-10x}{2\sqrt{x}} \right)}{x} \\\\\\ \cfrac{dy}{dx}=\cfrac{ \frac{(4x-10)(\sqrt{x})(2\sqrt{x})~~-~~(2x^2-10x)}{2\sqrt{x}}}{x} \\\\\\ \cfrac{dy}{dx}=\cfrac{(4x-10)(\sqrt{x})(2\sqrt{x})~~-~~(2x^2-10x)}{2x\sqrt{x}}


\bf \cfrac{dy}{dx}=\cfrac{(4x-10)2x~~-~~(2x^2-10x)}{2x\sqrt{x}}\implies \cfrac{dy}{dx}=\cfrac{8x^2-20x~~-~~(2x^2-10x)}{2x\sqrt{x}} \\\\\\ \cfrac{dy}{dx}=\cfrac{8x^2-20x~~-~~2x^2+10x}{2x\sqrt{x}} \implies \cfrac{dy}{dx}=\cfrac{6x^2-10x}{2x\sqrt{x}} \\\\\\ \cfrac{dy}{dx}=\cfrac{2x(3x-5)}{2x\sqrt{x}}\implies \cfrac{dy}{dx}=\cfrac{3x-5}{\sqrt{x}}

8 0
3 years ago
What is the vertex of the graph of the function f(x) = x2 − 4x?
Vsevolod [243]

Answer:

(2, -4).

Step-by-step explanation:

x^2 - 4x

= (x - 2)^2 - 4.

So the vertex is at

(2, -4).

6 0
3 years ago
Read 2 more answers
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