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Law Incorporation [45]
3 years ago
6

Correct answers only please! I keep losing points...

Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
7 0

Answer:

A = $ 7,299.92

A = P + I where

P (principal) = $ 6,000.00

I (interest) = $ 1,299.92

Step-by-step explanation:

A = P(1 + r/n)nt

Where:

A = Accrued Amount (principal + interest)

P = Principal Amount

I = Interest Amount

R = Annual Nominal Interest Rate in percent

r = Annual Nominal Interest Rate as a decimal

r = R/100

t = Time Involved in years, 0.5 years is calculated as 6 months, etc.

n = number of compounding periods per unit t; at the END of each period

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Ron used 121 congruent equilateral triangles with 2 cm side lengths to form one large equilateral triangle. What is the perimete
Pepsi [2]
The number of smaller triangles along one side of the larger triangle is the square root of the total number of triangles. The perimeter of the large triangle is ...
  3*(2 cm)*√121 = 66 cm
5 0
3 years ago
I need help please! I've been stuck on this for a week and its really stressful lol
worty [1.4K]

Answer:

y=0.2*4^{x}

Step-by-step explanation:

Notice when x increases 1, y is 4 times the previous one, so

the function is like y=C*4^{x}

To determine the constant C, put any pair of (x, y)

Use x = 0, y = 0.2, so

0.2 = C*4^{0} = C * 1 = C

then y=0.2*4^{x}

5 0
2 years ago
Read 2 more answers
Please find the exact length of the midsegment of trapezoid JKLM with vertices J(6, 10), K(10, 6), L(8, 2), and M(2, 2). Thank y
I am Lyosha [343]

Answer:

the exact length of the midsegment of trapezoid JKLM  = \mathbf{ = 3 \sqrt{5} } i.e 6.708 units on the graph

Step-by-step explanation:

From the diagram attached below; we can see a graphical representation showing the mid-segment of the trapezoid JKLM. The mid-segment is located at the line parallel to the sides of the trapezoid. However; these mid-segments are X and Y found on the line JK and LM respectively from the graph.

Using the expression for midpoints between two points to determine the exact length of the mid-segment ; we have:

\mathbf{ YX = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} }

\mathbf{ YX = \sqrt{(8-5)^2+(8-2)^2} }

\mathbf{ YX = \sqrt{(3)^2+(6)^2} }

\mathbf{ YX = \sqrt{9+36} }

\mathbf{ YX = \sqrt{45} }

\mathbf{ YX = \sqrt{9*5} }

\mathbf{ YX = 3 \sqrt{5} }

Thus; the exact length of the midsegment of trapezoid JKLM  = \mathbf{ = 3 \sqrt{5} } i.e 6.708 units on the graph

8 0
3 years ago
What does this equal​
Anton [14]
In simplify the expression =
1.56 • 10^52 + 3.5 • 10^48
5 0
3 years ago
Find the equation of a circle with a center at (0, -4) and a point on the circle is (6, 0).
EastWind [94]

Answer:

x^2 + ( y + 4)^2 = 52

Step-by-step explanation:

Equation of circle with center (a , b) and radius, r is :

(x -a)^2 + ( y -b)^2 = r^2

Given :  a = 0 , b = - 4

Step 1 : Find the radius.

       Given ( 6 , 0 ) lies on the circle. Therefore the distance between the center (0 , - 4) of the circle and ( 6 , 0 ) gives the radius of the circle.

   r = \sqrt{( 0 - 6)^2 + ( -4 - 0)^2} \\\\

     = \sqrt{ 36 + 16 } \\\\= \sqrt{52}

Step 2 : Equation of circle.

  (x - 0)^2 + (y -( - 4))^2 = (\sqrt{52})^2\\\\x^2 + ( y+ 4)^2 = 52

8 0
3 years ago
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