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Contact [7]
3 years ago
7

You own a yacht which is 14.5 meters long. It is motoring down a canal at 10.6 m/s. Its bow (the front of the boat) is just abou

t to begin passing underneath a bridge that is 30.0 m across. How much time is required until its stern (the end of the boat) is no longer under the bridge?
Physics
1 answer:
Alex73 [517]3 years ago
5 0

Answer:

4.198 seconds

Explanation:

The total length of the yacht is 30m and the width of the bridge is 14.5m.

The speed of the yacht is 10.6m/s.

We can assume the current of the canal has a speed of 0m/s.

To calculate the answer we will break it into two parts

1) The time it takes for the bow to travel from the start of the bridge to the end

<em>Formula Speed = Distance / Time</em>

Speed = 10.6m/s

Distance = 30m

Time = T1

T1 = 2.8301s

2) The time it takes for the stern to cross the end of the bridge after the bow

<em />

<em>Formula Speed = Distance / Time</em>

<em />

Speed = 10.6m/s

Distance = 14.5m

Time = T2

T2 = 1.3679s

3) The Total Time is

Total = T1 + T2

Total = 4.198s

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Read 2 more answers
A spring is hung vertically with a 425g mass attached to it. The mass is at rest. If the mass causes the spring to stretch 0.67
egoroff_w [7]

Answer:

6.22 N/m

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From Hooke's law we deduce that F=kx where F is the applied force and k is the spring constant while x is the extension or compression of the spring. Making k the subject of the above formula then

k=\frac {F}{x}

We also know that the force F is equal to mg where m is the mass of an object and g is acceleration due to gravity hence substituting F with mg we get that

k=\frac {mg}{x}

Substituting m with 425 g which is equivalent to 0.425 kg and g with 9.81 then 0.67 for x we get that

k=\frac {mg}{x}=\frac {0.425\times 9.81}{0.67}=6.222761194 N/m\approx 6.22\ N/m

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