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Deffense [45]
3 years ago
10

Light incident on a glass sheet is partly reflected and partly refracted. How is the reflected ray different from the refracted

ray?
A.
The refracted ray is unpolarized whereas the reflected ray is horizontally polarized.
B.
The refracted ray is unpolarized whereas the reflected ray is vertically polarized.
C.
The refracted ray is horizontally polarized whereas the reflected ray is unpolarized.
D.
The refracted ray is vertically polarized whereas the reflected ray is unpolarized.
E.
The refracted ray is vertically polarized whereas the reflected ray is horizontally polarized.
Physics
1 answer:
kkurt [141]3 years ago
7 0

Answer:

E. The refracted ray is vertically polarized whereas the reflected ray is horizontally polarized.

Explanation:

#PLATOLIVESMATTER

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4 years ago
Calculate the force of gravity on a spacecraft 12800 km (2 earth radii) above the earth's surface if its mass is 1600 kg. n (tow
Maksim231197 [3]
Since the spacecraft is two earth radii the surface of the earth, it is three earth radii above the center.

Given: Radius of the earth re = 6.38 x 10⁶ m  r = 1.91 x 10⁷ m

           Mass of the spacecraft Ms = 1600 Kg

           Mass of the earth Me = 5.98 x 10²⁴ Kg

           G = 6.67 X 10⁻¹¹ N.m²/Kg²

Formula: F = GMeMs/r²

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8 0
3 years ago
2. If you exert a force of 10.0 N to lift a box a distance of 0.9 m, how much work have you done?
KonstantinChe [14]
<span> force of 10.0 N
</span>
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6 0
3 years ago
Read 2 more answers
I’m not sure how to solve this
spayn [35]

Answer:

Option 10. 169.118 J/KgºC

Explanation:

From the question given above, the following data were obtained:

Change in temperature (ΔT) = 20 °C

Heat (Q) absorbed = 1.61 KJ

Mass of metal bar = 476 g

Specific heat capacity (C) of metal bar =?

Next, we shall convert 1.61 KJ to joule (J). This can be obtained as follow:

1 kJ = 1000 J

Therefore,

1.61 KJ = 1.61 KJ × 1000 J / 1 kJ

1.61 KJ = 1610 J

Next, we shall convert 476 g to Kg. This can be obtained as follow:

1000 g = 1 Kg

Therefore,

476 g = 476 g × 1 Kg / 1000 g

476 g = 0.476 Kg

Finally, we shall determine the specific heat capacity of the metal bar. This can be obtained as follow:

Change in temperature (ΔT) = 20 °C

Heat (Q) absorbed = 1610 J

Mass of metal bar = 0.476 Kg

Specific heat capacity (C) of metal bar =?

Q = MCΔT

1610 = 0.476 × C × 20

1610 = 9.52 × C

Divide both side by 9.52

C = 1610 / 9.52

C = 169.118 J/KgºC

Thus, the specific heat capacity of the metal bar is 169.118 J/KgºC

6 0
3 years ago
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