The right answer is. This kind of phase change--liquid<span> to </span>gas<span>--is </span>called<span> evaporation or vaporization. Water vapor can in </span>turn<span> be cooled to form </span>liquid<span> water. This kind of phase change--from</span>gas<span> to </span>liquid<span>--is referred to as condensation.</span>
Since the spacecraft is two earth radii the surface of the earth, it is three earth radii above the center.
Given: Radius of the earth re = 6.38 x 10⁶ m r = 1.91 x 10⁷ m
Mass of the spacecraft Ms = 1600 Kg
Mass of the earth Me = 5.98 x 10²⁴ Kg
G = 6.67 X 10⁻¹¹ N.m²/Kg²
Formula: F = GMeMs/r²
F = (6.67 X 10⁻¹¹ N.m²/Kg²)(5.98 x 10²⁴ Kg)(1,600 Kg)/(1.91 x 10⁷ m)²
F = 6.38 X 10¹⁷ N/3.65 X 10¹⁴ m²
F = 1,748.5 N
I didnt want to type it all so here is the link that tells you all you need to answer that question
https://kids.kiddle.co/Electron_cloud
<span> force of 10.0 N
</span>
<span>distance of 0.9 m
w=f*d
w=10*0.9
=9.0 j</span>
Answer:
Option 10. 169.118 J/KgºC
Explanation:
From the question given above, the following data were obtained:
Change in temperature (ΔT) = 20 °C
Heat (Q) absorbed = 1.61 KJ
Mass of metal bar = 476 g
Specific heat capacity (C) of metal bar =?
Next, we shall convert 1.61 KJ to joule (J). This can be obtained as follow:
1 kJ = 1000 J
Therefore,
1.61 KJ = 1.61 KJ × 1000 J / 1 kJ
1.61 KJ = 1610 J
Next, we shall convert 476 g to Kg. This can be obtained as follow:
1000 g = 1 Kg
Therefore,
476 g = 476 g × 1 Kg / 1000 g
476 g = 0.476 Kg
Finally, we shall determine the specific heat capacity of the metal bar. This can be obtained as follow:
Change in temperature (ΔT) = 20 °C
Heat (Q) absorbed = 1610 J
Mass of metal bar = 0.476 Kg
Specific heat capacity (C) of metal bar =?
Q = MCΔT
1610 = 0.476 × C × 20
1610 = 9.52 × C
Divide both side by 9.52
C = 1610 / 9.52
C = 169.118 J/KgºC
Thus, the specific heat capacity of the metal bar is 169.118 J/KgºC