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2 years ago

10

Light incident on a glass sheet is partly reflected and partly refracted. How is the reflected ray different from the refracted

ray?
A.
The refracted ray is unpolarized whereas the reflected ray is horizontally polarized.
B.
The refracted ray is unpolarized whereas the reflected ray is vertically polarized.
C.
The refracted ray is horizontally polarized whereas the reflected ray is unpolarized.
D.
The refracted ray is vertically polarized whereas the reflected ray is unpolarized.
E.
The refracted ray is vertically polarized whereas the reflected ray is horizontally polarized.

1 answer:

kkurt [141]2 years ago

7 0

Answer:

E. The refracted ray is vertically polarized whereas the reflected ray is horizontally polarized.

Explanation:

#PLATOLIVESMATTER

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Answer:

The work done by gravity during the roll is 490.6 J

Explanation:

The work (W) is:

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$F = W_{x} = mgsin(\theta)$

<em>Where:</em>

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$W = F*d = 24.53 N*20 m = 490.6 J$

Therefore, the work done by gravity during the roll is 490.6 J.

I hope it helps you!

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2 years ago

Wire sizes are often reported using the AWG (American Wire Gauge) system in which smaller diameter wires are said to be of highe

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Answer:

Explanation:

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Given that,

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Time =5.40 s

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Using formula of displacement

$s=r_{2}-r_{1}$

Where, $r_{1}$ = initial position

$r_{2}$ = final position

Put the value into the formula

$s= (-4.10i + 3.30j + 5.40k)-(2.70i - 2.90j + 5.50k)$

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Put the value into the formula

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Where, P = power

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Put the value into the formula

$P=\dfrac{41.67}{5.40}$

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Put the value into the formula

$\theta=\cos^{-1}\dfrac{(-4.10i + 3.30j + 5.40k)\cdot(2.70i - 2.90j + 5.50k)}{7.54\times6.778})$

$\theta=79.7^{\circ}$

Hence, (a). The work done on the object by the force in the 5.40 s interval is 41.67 J.

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(c). The angle between vectors is 79.7°

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3 years ago

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antiseptic1488 [7]

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2 years ago