Answer:
A. 
B. 
C. 
D. 
Step-by-step explanation:
A. To solve the first part of the problem we must replace
in the function 
So:

B. In part B we must find the inverse function of 
To find the inverse function do 

Now clear the variable x.

Replace x with y.

Finally

C. Now we take the inverse function found above and replace 

D. Now we substitute
in the original function.

Answer:
#1
Step-by-step explanation:
Hope this helps! <3
Answer:
option B.
About 16% of the books have fewer than 150 pages
Step-by-step explanation:
Since we are dealing with a normal distribution
68.27% of the values will fall in the range with the standard deviation
(180-30 , 180+30) = (150, 210)
Approximately 15.86% of the values will be higher than 210
and the rest 15.86% will be lower than 150
So the correct answer is option B.
About 16% of the books have fewer than 150 pages
A
evaluate f(5) and f(2)
f(5) = 5m + b and f(2) = 2m + b, hence
f(5) - f(2) = 5m + b - 2m - b = 3m
the expression simplifies to
= 2 ( cross- multiply )
3m = 6 ( divide both sides by 3 )
m = 2 → A