Answer:
C = 1.01
Explanation:
Given that,
Mass, m = 75 kg
The terminal velocity of the mass, 
Area of cross section, 
We need to find the drag coefficient. At terminal velocity, the weight is balanced by the drag on the object. So,
Weight of the object = drag force
R = W
or
Where
is the density of air = 1.225 kg/m³
C is drag coefficient
So,
So, the drag coefficient is 1.01.
Answer:
Explanation:
velocity of first projectile after 3 s
v = u - gt
v = 49.4 - 9.8 x 3
= 20 m /s
Velocity of second projectile after 3 s after being dropped from rest
v = u + gt
= 0 + 9.8 x 3
= 29.4 m /s
They will be moving in opposite direction at the time of meeting , so their relative velocity
= 20 + 29.4 = 49.4 m /s
From the frame of reference of the first projectile, the velocity of the second projectile will be 49.4 m /s .
Once it leaves the circle, it'll continue in a straight line, in the direction it was moving when it left the circle.
To solve this problem it is necessary to apply the concept related to the definition of Density. Density is defined as the relationship between volume and mass. The greater the volume with respect to the mass, the smaller the mass tends to be and vice versa. By definition it is given by the formula:
Where,
V= Volume
m = Mass
From the data given we have to,
1g of the alloy will contain 0.61g Cu, 0.335g Zn and 0.05g Pb
Therefore if we calculate the volume of each element we have,
The density of the alloy would be
Therefore the density of the alloy is 
Answer:
They both arrive at 1:00 PM
Explanation:
Amount Davien has to drive : 40km
Amount Jackson has to drive = 50km
Davien moves at 40km/h,
Therefore, it only takes Davien 1 hour to get there.
12:00 PM + 1 hour = 1:00 PM
Jackson moves 100km/h
He needs to drive 50 min, so 50/100 = 1/2
It takes him half an hour, or 30minutes
If he leaves at 12:30, then he gets there at 1:00 PM
