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Anastaziya [24]
3 years ago
10

Writers periodically compete to see who can write the longest sentence in literature. James Joyce long held the English record w

ith a 4,391 word sentence in Ulysses. Jonathan Coe one-uped him in 2001 with a 13,955 word sentence in The Rotter’s Club. More recently, a single-sentence, 469,375 word novel appeared.Writers periodically compete to see who can write the longest sentence in literature. James Joyce long held the English record with a 4,391 word sentence in Ulysses. Jonathan Coe one-uped him in 2001 with a 13,955 word sentence in The Rotter’s Club. More recently, a single-sentence, 469,375 word novel appeared.
Writers periodically compete to see who can write the longest sentence in literature. James Joyce long held the English record with a 4,391 word sentence in Ulysses. Jonathan Coe one-uped him in 2001 with a 13,955 word sentence in The Rotter’s Club. More recently, a single-sentence, 469,375 word novel appeared.
Writers periodically compete to see who can write the longest sentence in literature. James Joyce long held the English record with a 4,391 word sentence in Ulysses. Jonathan Coe one-uped him in 2001 with a 13,955 word sentence in The Rotter’s Club. More recently, a single-sentence, 469,375 word novel appeared.
Writers periodically compete to see who can write the longest sentence in literature. James Joyce long held the English record with a 4,391 word sentence in Ulysses. Jonathan Coe one-uped him in 2001 with a 13,955 word sentence in The Rotter’s Club. More recently, a single-sentence, 469,375 word novel appeared.
Writers periodically compete to see who can write the longest sentence in literature. James Joyce long held the English record with a 4,391 word sentence in Ulysses. Jonathan Coe one-uped him in 2001 with a 13,955 word sentence in The Rotter’s Club. More recently, a single-sentence, 469,375 word novel appeared.
Physics
1 answer:
Scorpion4ik [409]3 years ago
8 0

Answer:

Explanation:

Writers periodically compete to see who can write the longest sentence in literature. James Joyce long held the English record with a 4,391 word sentence in Ulysses. Jonathan Coe one-uped him in 2001 with a 13,955 word sentence in The Rotter’s Club. More recently, a single-sentence, 469,375 word novel appeared.Writers periodically compete to see who can write the longest sentence in literature. James Joyce long held the English record with a 4,391 word sentence in Ulysses. Jonathan Coe one-uped him in 2001 with a 13,955 word sentence in The Rotter’s Club. More recently, a single-sentence, 469,375 word novel appeared.

Writers periodically compete to see who can write the longest sentence in literature. James Joyce long held the English record with a 4,391 word sentence in Ulysses. Jonathan Coe one-uped him in 2001 with a 13,955 word sentence in The Rotter’s Club. More recently, a single-sentence, 469,375 word novel appeared.

Writers periodically compete to see who can write the longest sentence in literature. James Joyce long held the English record with a 4,391 word sentence in Ulysses. Jonathan Coe one-uped him in 2001 with a 13,955 word sentence in The Rotter’s Club. More recently, a single-sentence, 469,375 word novel appeared.

Writers periodically compete to see who can write the longest sentence in literature. James Joyce long held the English record with a 4,391 word sentence in Ulysses. Jonathan Coe one-uped him in 2001 with a 13,955 word sentence in The Rotter’s Club. More recently, a single-sentence, 469,375 word novel appeared.

Writers periodically compete to see who can write the longest sentence in literature. James Joyce long held the English record with a 4,391 word sentence in Ulysses. Jonathan Coe one-uped him in 2001 with a 13,955 word sentence in The Rotter’s Club. More recently, a single-sentence, 469,375 word novel appeared.

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What could be the possible answer to the question ?<br><br>thankyou ~​
Ganezh [65]

The value of the force, F₀, at equilibrium is equal to the horizontal

component of the tension in string 2.

Response:

  • The value of F₀ so that string 1 remains vertical is approximately <u>0.377·M·g</u>

<h3>How can the equilibrium of forces be used to find the value of F₀?</h3>

Given:

The weight of the rod = The sum of the vertical forces in the strings

Therefore;

M·g = T₂·cos(37°) + T₁

The weight of the rod is at the middle.

Taking moment about point (2) gives;

M·g × L = T₁ × 2·L

Therefore;

T_1 = \mathbf{\dfrac{M \cdot g}{2}}

Which gives;

M \cdot g = \mathbf{T_2 \cdot cos(37 ^{\circ})+ \dfrac{M \cdot g}{2}}

T_2 = \dfrac{M \cdot g - \dfrac{M \cdot g}{2}}{cos(37 ^{\circ})}  = \mathbf{\dfrac{M \cdot g}{2 \cdot cos(37 ^{\circ})}}}

F₀ = T₂·sin(37°)

Which gives;

F_0 = \dfrac{M \cdot g \cdot sin(37 ^{\circ})}{2 \cdot cos(37 ^{\circ})}} = \dfrac{M \cdot g \cdot tan(37 ^{\circ})}{2}  \approx  \mathbf{0.377  \cdot M \cdot g}

  • F₀ ≈ <u>0.377·M·g</u>

<u />

Learn more about equilibrium of forces here:

brainly.com/question/6995192

3 0
2 years ago
Read 2 more answers
A car is driving at 99 km/h, calculate the distance it travels in 70 minutes.
Lapatulllka [165]

Answer:

The distance the car travels is 115500 m in S.I units

Explanation:

Distance d = vt where v = speed of the car and t = time taken to travel

Now v = 99 km/h. We now convert it to S.I units. So

v = 99 km/h = 99 × 1000 m/(1 × 3600 s)

v = 99000 m/3600 s

v = 27.5 m/s

The speed of the car is 27.5 m/s in S.I units

We now convert the time t = 70 minutes to seconds by multiplying it by 60.

So, t = 70 min = 70 × 60 s = 4200 s

The time taken to travel is 4200 s in S.I units

Now the distance, d = vt

d = 27.5 m/s × 4200 s

d = 115500 m

So, the distance the car travels is 115500 m in S.I units

8 0
3 years ago
Please i need detailed explanation​
zubka84 [21]

Answer:

2Micro Farahds

Explanation:

Its in the picture.

I Hope it helps.

4 0
3 years ago
A 3.00 kg mud ball has a perfectly inelastic collision with a second mud ball that is initially at rest. the composite system mo
viva [34]
Perfectly inelastic collision is type of collision during which two objects collide, stay connected and momentum is conserved. Formula used for conservation of momentum is:

m_{1} * v_{1} +  m_{2} * v_{2} =  m_{1} * v'_{1} +  m_{2} * v'_{2}

In case of perfectly inelastic collision v'1 and v'2 are same.

We have following information:
m₁=3 kg
m₂=? kg
v₁=x m/s
v₂=0 m/s
v'1 = v'2 = 1/3 * v₁

Now we insert given information and solve for m₂:
3*v₁ + 0*? = 3*1/3*v₁ + m₂*1/3*v₁
3v₁ = v₁ + m₂*1/3*v₁
2v₁ = m₂*1/3*v₁
2 = m₂*1/3
m₂= 6kg

Mass of second mud ball is 6kg.
7 0
3 years ago
Which kinds of objects emit visible light in the electromagnetic spectrum?
Triss [41]

Answer : Relatively hot objects

Explanation : We know that, the temperature of the objects is inversely proportional to their wavelengths. The objects emitting radiation in the visible region have short wavelength and hence are relatively hotter.

We know the range of wavelength of the visible spectrum is from 400 nm to 780 nm.





3 0
3 years ago
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