Answer:
A (2066,6 N)
Explanation:
Use the Work formula
62.000J = F . 30
62.000/30 = 2066,6 N
The amout of time it took to move the rock doesn´t matter at all.
It is called a distraction variable, We don´t need it to solve the problem it is there just to confuse.
Answer:
thats a lot, which one u want me to do?
Explanation:
Answer:
She covers the distance is 12 km.
The magnitude of displacement is 8.6 km.
The direction of her displacement is north east.
Explanation:
Given that,
Christina drives his moped 7 kilometers North and stop for lunch and then drive 5 km east.
We need to calculate the total distance
Using formula of distance
Put the value into the formula
We need to calculate the magnitude of displacement
Using formula of displacement
The direction of her displacement is north east.
Hence, She covers the distance is 12 km.
The magnitude of displacement is 8.6 km.
The direction of her displacement is north east.
Answer:
As the mass of an object increases, its gravitational force increases.
As an object's distance to other objects increases, its gravitational force on those objects increases.
Explanation:
The gravitational force of one object on another is calculated with the equation
F = (G*m1*m2)/(r²),
where G is the gravitational constant,
M1 and M2 are the masses of the two objects, and
r is the distance between them
We can see that the force has a direct relationship with both of the mass values, and an inverse square relationship with the distance between them.
Hope this helped!
a)You throw a stone horizontally at a speed of 5.0 m/s from the top of a cliff that is 78.4 m high.
from above statement we got
height = 78.4 m
since the ball is thrown, so its vertical velocity would be zero
u = 0
taking g = 9.8m/s^2
now, using the equation of motion
h = ut + gt^2/2
now putting all the values in it
we got ,
78.4 = 9.8 * t^2/ 2
by solving we got,
t = 4 sec
b) now, since along the horizontal , no force acting and accelaration is zero so
R = ut , R is RANGE
R = 5 * 4
range = 20 m
c) vertical components of the stone’s velocity just before it hits the ground = v sin θ =
horizontal components of the stone’s velocity just before it hits the ground = v cos θ
To know more about velocity visit :
brainly.com/question/18084516
#SPJ9
