Answer:
The density of the crystal is 10.22 g/cm³
Explanation:
Step 1: Data given
Molybdenum (Mo) has a BCC crystal structure
atomic radius = 0.1363 nm
atomic weight of 95.94 g/mol
Step 2: Calculate density of a bcc crystal
Density ρ= (nA
*Mo)/(Vc*Na)
⇒For BCC, n = 2 atoms/unit cell, and realizing that V
c = a
³
a = 4R/√3
Vc =(4R/√3)³
AMo = atomic weight = 95.94 g/mol
ρ = (n*A
Mo)/((4R/√3)³ *Na)
⇒with n = 2 atoms/unit cell
⇒ with AMo = 95.94 g/mol
⇒ with Vc =(4R/√3)³ = (4*0.1363*10-7 cm)³ /(√3)³
⇒with Na = 6.022*10^23 atoms/mol
ρ =10.22 g/cm³
The density of the crystal is 10.22 g/cm³
