All categories

3 years ago

Please help me with this:(

Mathematics

1 answer:

dolphi86 [110]3 years ago

5 0

Answer:

Y = 32.7°

Step-by-step explanation:

We will apply the Cosine law in the given triangle XYZ,

x = 90 ft

y = 55 ft

z = 50 ft

We have to find the measure of angle Y.

y² = x² + z² - 2xzCosY

(55)² = (90)² + (50)² - 2(90)(50)cosY

3025 = 8100 + 2500 - 9000.cosY

9000.cosY = 10600 - 3025

cosY = $\frac{7575}{9000}$

= 0.84167

Y = $\text{cos}^{-1}(0.84167)$

Y = 32.68 ≈ 32.7°

Therefore, measure of angle Y = 32.7°

You might be interested in

HELP ME PLEASE!!!!!!!!!!!

Angelina_Jolie [31]

Not linear .........

3 0

2 years ago

A rectangular room is 12 1/2 feet long and 10 1/3 feet wide. what is the area of the room

beks73 [17]

Answer:

The area is 775/6 square ft²

Step-by-step explanation:

Multiply 12 1/2 by 10 1/3 to find the area

6 0

3 years ago

(d) Given that n(§) = 96, n(A) = 50 and n(B) = 60. Find the maximum and minimum values for n(An B).

frez [133]

Step-by-step explanation:

the max. value is when the smaller set (A) is completely contained in the larger set (B).

then n(A n B) is n(A) = 50.

the set intersection between A and B cannot get bigger than that. or A gets bigger ...

after all, the intersection means it is a set of all elements that exist in BOTH sets.

but then there must be other elements besides A and B in the universal set too, because n(universal set) = 96, and n(A u B) would be only 60.

the min. value could be the empty set or 0. but because n(universal set) = 96, and n(A) + n(B) = 110 and larger than 96, it means that there have to be some shared elements. at least 110 - 96 = 14 elements.

in this case there cannot be other elements in the universal set than A and B. and n(universal set) = n(AuB) = 96.

3 0

1 year ago

48 m

g100num [7]

Answer:

Answer in terms of π=144π m^3

Answer by replacing π with 3.14 is 452.16 approximately 452.2m^3

Answer to the nearest whole no. is 452m^3

Step-by-step explanation:

$volume \: of \: a \: cone = \frac{1}{3} \pi {r}^{2} h$

$radius = \frac{diametre}{2}$

$radius = 24$

$height = 18$

$slant \: height \: = 30$

$first \: step$

$the \: exact \: volume \: of \: the \: cone \: in \: terms \: of \: \pi$

$v = \frac{1}{3} \pi {r}^{2} h$

$\: \: = \frac{1}{3} \times \pi \times 24 \times 18$

$\: \: \: = \frac{432\pi}{3}$

$\: \: \: = 144\pi$

$second \: step$

$approximate \: answer \: using \: 3.14 \: in \: place \: of \: \pi$

$144 \times 3.14$

$= 452.16$

$approximately \: 452.2$

$last \: step$

$answer \: to \: the \: nearest \: whole \: number$

$452 {m}^{3}$

7 0

3 years ago

Can a triangle have lengths of 1, 16, and 16 ...Can anyone help ?

FinnZ [79.3K]

Answer:

Yes they can it would be a isosceles triangle.

Step-by-step explanation:

An isosceles triangle can have 1 side that is different from the other 2.

6 0

3 years ago

Read 2 more answers