Hey Robby, your answer should be
f(x)= 20<span>(2.5)x</span>
Goodluck!
Answer:
0
Step-by-step explanation:
0/57 is going to be 0 since you have 0 out of 57 pizzas.
Split it up an group with like ones (6x^3 with 2x since 6 and 2 are divisble by 2 and 9x^2 with 3 since both divisible by 3)
(6x^3+2x)+(9x^2+3)
undistribute using reverse distributive property (ab+ac=a(b+c))
2x(3x^2+1)+3(x^2+1)
undistribute again
(3x^2+1)(2x+3)
Answer:
All potential roots are 3,3 and .
Step-by-step explanation:
Potential roots of the polynomial is all possible roots of f(x).
Using rational root theorem test. We will find all the possible or potential roots of the polynomial.
p=All the positive/negative factors of 45
q=All the positive/negative factors of 3
All possible roots
Now we check each rational root and see which are possible roots for given function.
Similarly, we will check for all value of p/q and we get
Thus, All potential roots are 3,3 and .
Answer:
1) HL=15
2)EF=23
Step-by-step explanation: