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Semenov [28]
3 years ago
9

Carol has several test tubes of different liquids. If Carol removes heat from the liquid substances, which of the following is m

ost likely to occur?
a The temperature of the particles will decrease and then become a gas.
b The temperature of the particles will increase and then become solid.
c The temperature of the particles will increase and then become gases.
d The temperature of the particles will decrease and take up less space.
Physics
1 answer:
Archy [21]3 years ago
6 0

Answer:

d

Explanation:

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I could be wrong but I believe it’s 1/2
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8 0
3 years ago
Sound waves with a constant frequency of 250 hertz are traveling through air at stp. what is the wavelength of the sound waves
Deffense [45]

Answer:

wave length is 1.2m

Explanation:

since formula of wave length is v/f

v(speed of sound in air at stp is 300ms^-1)

f(frequency 250hertz)

then wave length is 300÷250 which give 1.2m

5 0
1 year ago
What is the torque τa about axis a due to the force f⃗ ? express the torque about axis a at cartesian coordinates (0,0)?
pentagon [3]

Answer:

\tau_a = F a sin \theta

Explanation:

The torque of a force is given by:

\tau = F d sin \theta

where

F is the magnitude of the force

d is the distance between the point of application of the force and the centre of rotation of the system

\theta is the angle between the direction of the force and d

In this problem, we have:

F, the force

a, the distance of application of the force from the centre (0,0)

\theta, the angle between the direction of the force and a

Therefore, the torque is

\tau_a = F a sin \theta

5 0
3 years ago
(a) At what height above Earth’s surface is the energy required to lift a satellite to that height equal to the kinetic energy r
Nikitich [7]

Answer:

Explanation:

Gravitational Potential Energy at earth surface U_1=\frac{GM_em}{R_e}

Gravitational Potential Energy at height h is U_2=\frac{GM_em}{R_e+h}

Energy required to lift the satellite E_1=U_1-U_2

E_1=\frac{GM_em}{R_e}-\frac{GM_em}{R_e+h}

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\Delta E=E_1-E_2

\Delta E=\frac{GM_em}{R_e}-\frac{GM_em}{R_e+h}-\frac{GM_2m}{2(R_e+h)}

E_1=E_2  (given)

\frac{GM_em}{R_e}-\frac{GM_em}{R_e+h}-\frac{GM_2m}{2(R_e+h)}=0

\frac{1}{R_e}-\frac{3}{2(R_e+h)}=0

h=\frac{R_e}{2}

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(b)For greater height E_1  is greater than E_2

thus energy to lift the satellite is more than orbiting around earth

4 0
2 years ago
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