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3 years ago

7

When it is brought near a neutral object, a charged object can _________ a charge in a neutral object.A) induce, B) cancel,C) ne

utralize, D) add or subtract

1 answer:

Bess [88]3 years ago

3 0

The answer is a induce.

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A paper clip that has a mass of 1.5 grams is thrown into the air and initially has a kinetic energy

Vsevolod [243]

Answer:

$v = 4.2 \ m/s$

Explanation:

Given data:

Mass of the paper clip, $m = 1.5 \ g = 0.0015 \ kg$

Kinetic energy, $K = 0.013 \ \rm J$

Let the velocity of the paper clip when it is thrown be <em>v</em>.

Thus,

$K = \frac{1}{2}mv^{2}$

$0.013 = 0.5 \times 0.0015 \times v^{2}$

$\Rightarrow \ v = 4.16 \ m/s$

$v = 4.2 \ m/s.$ (rounding to nearest tenth)

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3 years ago

How are vectors added and subtracted

blagie [28]

Place the next vector with its tail at the previous vector's head. ... To subtract vectors, proceed as if adding the two vectors, but flip the vector to be subtracted across the axes and then join it tail to head as if adding. Adding or subtracting any number of vectors yields a resultant vector.

Explanation:

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2 years ago

Water at a gauge pressure of 3.8 atm at street level flows into an office building at a speed of 0.68 m/s through a pipe 5.4 cm

Nataliya [291]

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3 years ago

In the process of photosynthesis, how do plants obtain the water, carbon dioxide, and energy they use for this process?

NNADVOKAT [17]

Answer:

They get it from the air and soil. They also take energy from the sun.

Explanation:

During photosynthesis, plants take in carbon dioxide (CO2) and water (H2O) from the air and soil.

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2 years ago

If the mass is displaced 0.270 m from equilibrium and released, what is its speed when it is 0.130 m from equilibrium?

puteri [66]

Answer:

The speed is 1.52 m.

Explanation:

Given that,

Displacement =0.270 m

Distance = 0.130 m

Suppose a 0.321-kg mass is attached to a spring with a force constant of 13.3 N/m.

We need to calculate the angular velocity

Using formula of angular velocity

$\omega=\sqrt{\dfrac{k}{m}}$

Put the value into the formula

$\omega=\sqrt{\dfrac{13.3}{0.321}}$

$\omega=6.43\ rad/s$

We need to calculate the velocity

Using formula of velocity

$v=\omega\sqrt{A^2-x^2}$

Put the value into the formula

$v=6.43\times\sqrt{0.270^2-0.130^2}$

$v=1.52\ m/s$

Hence, The speed is 1.52 m.

6 0

3 years ago