Answer:
So visible wavelength which is possible here is
416 nm and 693.3 nm
Explanation:
As we know that for normal incidence of light the path difference of the reflected ray is given as
so here we can say that for maximum intensity condition we will have
so we have
now for visible wavelength we have
for N = 1
for N = 2
for N = 3
Are you familiar with any basic calculus? If so, we can just look at this derivative and see what's happening with our units here..
Here it shows that acceleration is the derivative of velocity with respect to time. In other words, we can say that:
We can read that equation as: "acceleration is the change of velocity divided by the change in time (aka the time interval)."
If you're not familiar with calculus, we can use a simple equation of motion:
where:
vf = final velocity
vi = initial velocity
a = acceleration
t = observed time interval
We can rearrange this equation to find:
This is the same exact thing we wrote before!
