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2 years ago

7

When it is brought near a neutral object, a charged object can _________ a charge in a neutral object.A) induce, B) cancel,C) ne

utralize, D) add or subtract

1 answer:

Bess [88]2 years ago

3 0

The answer is a induce.

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Suppose you apply a flame to heat 1 liter of water and its temperature rises by 3 C. If you apply the same flame for the same le

kykrilka [37]

Answer:1 $^{0}C$

Explanation:

Let the heat given by flame be $h$ .

Let $m_{1}$ be the mass of water in case 1.

Let $m_{2}$ be the mass of water in case 2.

Let Δ $T_{1}$ be the temperature difference in case 1.

Let Δ $T_{2}$ be the temperature difference in case 2.

Let $V_{1}$ be the volume of water in case 1.

Let $V_{2}$ be the volume of water in case 2.

Let $d$ be the density of water.

Let $s$ be the specific heat of water.

Given,

$V_{1}=1L\\V_{2}=3L\\$

Δ $T_{1}=3^{0}C$

Since the same heat is given to water in both the cases,

$h=m_{1}s$ Δ $T_{1}$

$h=m_{2}s$ Δ $T_{2}$

So, $m_{1}s$ Δ $T_{1}$ = $m_{2}s$ Δ $T_{2}$

Since mass is product of volume an density,

$V_{1}ds$ Δ $T_{1}$ = $V_{2}ds$ Δ $T_{2}$

$1\times d\times s\times 3=3\times d\times s\times$ Δ $T_{2}$

So,Δ $T_{2}=1^{0}C$

4 0

3 years ago

In electroplating, the object to be plated is which part of an electrolytic cell? cathode or anode

Bingel [31]

Since the anode dissolves and goes to the cathode. The object to be electroplated is kept at the cathode.

Please mark me as brainliest.

7 0

2 years ago

Read 2 more answers

In beachville, the last high tide occurred at 1:00 p.m. the next high tide will happen around _____. 1:25

Vladimir [108]

At Around 1:25 a.m. it will happen

8 0

3 years ago

Read 2 more answers

Sound waves are a longitudinal wave that have a speed of about 340 m/s when traveling through room temperature air. What is the

AlexFokin [52]

The wavelength of the wave is 0.055 m

Explanation:

The relationship between speed, frequency and wavelength of a wave is given by the wave equation:

$v=f\lambda$

where

v is the speed

f is the frequency

$\lambda$ is the wavelength

For the sound wave in this problem we have

v = 340 m/s is the speed

f = 6,191 Hz is the frequency

Solving for $\lambda$ , we find the wavelength:

$\lambda=\frac{v}{f}=\frac{340}{6191}=0.055 m$

Learn more about waves and wavelength:

brainly.com/question/5354733

brainly.com/question/9077368

#LearnwithBrainly

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3 years ago

A disk is uniformly accelerated from rest with angular acceleration α. The magnitude of the linear acceleration of a point on th

solniwko [45]

Answer:

$a = R\alpha\sqrt{1 + \alpha^2t^4}$

Explanation:

As we know that the acceleration of a point on the rim of the disc is in two directions

1) tangential acceleration which is given as

$a_t = R\alpha$

2) Centripetal acceleration

$a_c = \omega^2 R$

here we know that

$\omega = \alpha t$

$a_c = (\alpha t)^2 R$

now we know that net linear acceleration is given as

$a = \sqrt{a_c^2 + a_t^2}$

so we have

$a = \sqrt{R^2\alpha^2 + R^2(\alpha t)^4}$

$a = R\alpha\sqrt{1 + \alpha^2t^4}$

4 0

2 years ago