Answer:
he configuration with the highest electronic affinity is 2s2 2p5
Explanation:
Electronic affinity is the variation of energy when we add an electron to a neutral atom to form an ion
When an electron is added, it must occupy a space is the sub-level of the atom, giving more stability when it approaches the configuration of a complete shell with eight electrons (noble gas), so the affinity must increase when moving in a period Group VIII noble gases)
Let's examine the given settings
In this case, when adding an electron, 2s2 is very far from a complete level configuration, so its affinity must be small.
2s2 2p2 when adding an electro the one has a little more affinity, but is still a long way from a full shell, it would be missing 3 electrons
2s2 2sp5 this is the atom with the highest electronic affinity, since i = that when adding an electron the ion has the configuration of a noble gas. This is the most stable on the list
2s2 2p6 already has a full shell making it very difficult to insert an electron into this atom.
In summary, the configuration with the highest electronic affinity is 2s2 2p5
Answer:
oooh thats hard
Explanation:
well i would probaly search the page number or anthing on the page that should help
Answer:
I hear points of low volume sound and points of high volume of sound.
Explanation:
This is because, since the two sources of sound have the same frequency and are separated by a distance, d = 10 mm, there would be successive points of constructive and destructive interference.
Since their frequencies are similar, we should have beats of high and low frequency.
So, at points of low frequency, the amplitude of the wave is smallest and there is destructive interference. The frequency at this point is the difference between the frequencies from both speakers. Since the frequency from both speakers is 400 Hz, we have, f - f' = 400 Hz - 400 Hz = 0 Hz. So, the volume of the sound is low(zero) at these points.
Also, at points of high frequency, the amplitude of the wave is highest and there is constructive interference. The frequency at this point is the sum between the frequencies from both speakers. Since the frequency from both speakers is 400 Hz, we have, (f + f') = 400 Hz + 400 Hz = 800 Hz. So, the volume of the sound is high at these points.
So, as you wander around the room, I should hear points of high and low sound across the room.
Because even though the object got crush and misshape it still has the same identity. the identity never change
