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S_A_V [24]
3 years ago
14

Find the volume of this triangular prism. 6 cm 10 cm 7 cm

Mathematics
2 answers:
11111nata11111 [884]3 years ago
6 0
The volume of the triangular prism is 420
White raven [17]3 years ago
6 0

Answer:

210 cm³

Step-by-step explanation:

Volume of a triangular prism = \frac{1}{2\\} * B * L * H

                                                =\frac{1}{2} * 6cm * 10cm * 7cm

                                                =3cm * 10cm * 7cm

                                                =210 cm³

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Please help. will mark brainliest
Semmy [17]

DH = HF      

x + 1 = 3y         

y = (x + 1) ⁄ 3        


GH = HE

 3x – 4 = 5y + 1 

 y = (3x – 5) ⁄ 5 

            

 y = y 

 (x + 1) ⁄ 3 = (3x – 5) ⁄ 5 

5x + 5 = 9x – 15 

4x = 20 

 x = 5 


y = (x + 1) ⁄ 3        

y = (5 + 1) ⁄ 3       

y = 2 





4 0
3 years ago
Find the density of an object that has a volume of 20 cm3 and a mass of 56g
kherson [118]

Answer: 34y

Step-by-step explanation:

So first you have to round the nearest 2 to the nears 3 then you get 30 then you have to add 4 the add you variable.

7 0
3 years ago
Melanie makes $3.00 less per hour babysitting than her best friend, Carita. If the combined hourly rate of Melanie and Carita is
marysya [2.9K]

Answer:

B 6.00

Step-by-step explanation:

M= 6$

C= 9$

M+C= 6+9= 15$ per hour

3 0
3 years ago
I have a stamp collection. 70% of my stamps are Canadian and 30% are international. I have 500 more Canadian stamps than interna
shutvik [7]

Answer: N= 375, C= 875

Step-by-step explanation:  Let Canadian stamps=C

Let International stamps=N

C=875     and        N=375

 

C - 500=N,  .70(N + C) =C

Solve the following system:

{C-500 = N |     (equation 1)

0.7 (C+N) = C |     (equation 2)

Express the system in standard form:

{-N+C = 500 |     (equation 1)

0.7 N-0.3 C = 0 |     (equation 2)

Add 0.7 × (equation 1) to equation 2:

{-N+C = 500 |     (equation 1)

0 N+0.4 C = 350 |     (equation 2)

Divide equation 2 by 0.4:

{-N+C = 500 |     (equation 1)

0. N+C = 875. |     (equation 2)

Subtract equation 2 from equation 1:

{-N+0 C = -375. |     (equation 1)

0 N+C = 875. |     (equation 2)

Multiply equation 1 by -1:

{N+0 C = 375. |     (equation 1)

0 N+C = 875. |     (equation 2)

Collect results:

Answer: |  N = 375        and             C=875

3 0
2 years ago
An object is heated to 100°. It is left to cool in a room that
stepladder [879]

Answer:

Step-by-step explanation:

Use Newton's Law of Cooling for this one.  It involves natural logs and being able to solve equations that require natural logs.  The formula is as follows:

T(t)=T_{1}+(T_{0}-T_{1})e^{kt} where

T(t) is the temp at time t

T₁ is the enviornmental temp

T₀ is the initial temp

k is the cooling constant which is different for everything, and

t is the time (here, it's in minutes)

If we are looking first for the temp after 20 minutes, we have to solve for the k value.  That's what we will do first, given the info that we have:

T(t) = 80

T₁ = 30

T₀ = 100

t = 5

k = ?

Filling in to solve for k:

80=30+(100-30)e^{5k} which simplifies to

50=70e^{5k} Divide both sides by 70 to get

\frac{50}{70}=e^{5k} and take the natural log of both sides:

ln(\frac{5}{7})=ln(e^{5k})

Since you're learning logs, I'm assuming that you know that a natural log and Euler's number, e, "undo" each other (just like taking the square root of something squared).  That gives us:

-.3364722366=5k

Divide both sides by 5 to get that

k = -.0672944473

Now that we have a value for k, we can sub that in to solve for T(20):

T(20)=30+(100-30)e^{-.0672944473(20)} which simplifies to

T(20)=30+70e^{-1.345888946}

On your calculator, raise e to that power and multiply that number by 70:

T(20)= 30 + 70(.260308205) and

T(20) = 30 + 18.22157435 so

T(20) = 48.2°

Now we can use that k value to find out when (time) the temp of the object cools to 35°:

T(t) = 35

T₁ = 30

T₀ = 100

k = -.0672944473

t = ?

35=30+100-30)e^{-.0672944473t} which simplifies to

5=70e^{-.0672944473t}

Now divide both sides by 70 and take the natural log of both sides:

ln(\frac{5}{70})=ln(e^{-.0672944473t}) which simplifies to

-2.63905733 = -.0672944473t

Divide to get

t = 39.2 minutes

3 0
3 years ago
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