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UkoKoshka [18]
3 years ago
9

What is Keq for the reaction 2HCl(9) = H2(g) + Cl2(g)?

Chemistry
1 answer:
nirvana33 [79]3 years ago
8 0

Answer:

Keq= [(Cl2) (H2)] / (HCl)^2

Explanation:

Equilibrium Constant, Keq, is written as products/reactants.

So it's going to be Keq= [(Cl2) (H2)] / (HCl)^2

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A 4.00L flask containing Ne at 25 C and 6.00 atm is joined by a valve to an 8.00 L flask Ar at 25 C and 2.00 atm.
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Answer:

P=3.33atm

Explanation:

Hello!

In this case, since know the volume, temperature and pressure of the initial containers, we can compute the moles of each gas prior to the opening of the valve as shown below:

n_{Ne}=\frac{6atm*4L}{0.08206\frac{atm*L}{mol*K}*298.15K} =0.981molNe\\\\n_{Ar}=\frac{2atm*8L}{0.08206\frac{atm*L}{mol*K}*298.15K} =0.654molAr

Next, we add them up to obtain the total moles:

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Now, the total volume:

V_T=4.00L+8.00L=12.00L

Finally, the total pressure is computed by using the ideal gas equation:

P=\frac{1.635mol*0.08206\frac{atm*L}{mol*K}*298.15K}{12.00L}\\\\P=3.33atm

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