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UkoKoshka [18]
3 years ago
9

What is Keq for the reaction 2HCl(9) = H2(g) + Cl2(g)?

Chemistry
1 answer:
nirvana33 [79]3 years ago
8 0

Answer:

Keq= [(Cl2) (H2)] / (HCl)^2

Explanation:

Equilibrium Constant, Keq, is written as products/reactants.

So it's going to be Keq= [(Cl2) (H2)] / (HCl)^2

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Instead of 6 M NaOH being added to the solution, 6 M HCl is added. How will this affect the test for the presence of ammonium io
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Answer:

Ammonia gas(an alkaline gas with characteristics of choking or irritating smell) is not liberated when 6mole of HCl is added to the solution instead of 6mole of NaOH, to test for the presence of ammonium ion in the solution

Explanation:

As expected, when testing for ammonium ion in a solution (precisely ammonium salt solution), Sodium Hydroxide (NaOH) is required as the test reagent.

When NaOH is added to the solution, A gas with characteristics of choking or irritating smell is liberated.

This gas turn red litmus paper blue.

This liberated gas is an alkaline gas, which is confirmed as an ammonia gas(NH3).

If HCl is added instead of NaOH, the ammonia gas will not be liberated, which indicates that the test reagent used is wrong.

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Wich tools are appropriate to determine the densety of an irregular-shaped object ?
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a sample of fully saturated clay weighs 1350 g in its natural state and 975 g after drying. what is the natural water content of
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