What mass, in grams, of sodium sulfate is needed to make 234.9 g of a 1.7 % (m/m) aqueous solution of sodium sulfate?

What is the primary pigment found in the chlotopast

Lady_Fox [76]

Answer: Chlorophyll is a green photosynthetic pigment found in plants, algae, and cyanobacteria.

Chlorophyll absorbs mostly in the blue and to a lesser extent red portions of the electromagnetic spectrum, hence its intense green color.

Green substance in producers that traps light energy from the sun, which is then used to combine carbon dioxide and water into sugars in the process of photosynthesis Chlorophyll is vital for photosynthesis, which helps plants get energy from light.

Chlorophyll molecules are specifically arranged in and around pigment protein complexes called photosystems, which are embedded in the thylakoid membranes of chloroplasts.

Request: It would really help if you could make me brainliest

3 0

3 years ago

Explain why the metals conduct electricity

Whitepunk [10]

Answer:

Metals conduct electricity because the electrons inside the metal are relatively free to move. So when electricity is pass through metals, electrons carry electricity and spread it all over the metal. The mobility of electrons is the reason why metals conduct electricity.

5 0

3 years ago

Nitrogen dioxide is used industrially to produce nitric acid, but it contributes to acid rain and photochemical smog. What volum

Strike441 [17]

Answer:

35.41 L

Explanation:

Given, Volume of Copper = 4.84 cm³

Density = 8.95 g/cm³

Considering the expression for density as:

$Density=\frac {Mass}{Volume}$

So,

So, Mass= Density Volume = 8.95 g/cm³ 4.84 cm³ = 43.318 g

Mass of copper = 43.318 g

Molar mass of copper = 63.546 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{43.318\ g}{63.546\ g/mol}$

Moles of copper = 0.6817 moles

Given, Volume of nitric acid solution = 227 mL = 227 cm³

Density = 1.42 g/cm³

Considering the expression for density as:

$Density=\frac {Mass}{Volume}$

So,

So, Mass= Density Volume = 1.42 g/cm³ 227 cm³ = 322.34 g

Also, Nitric acid is 68.0 % by mass. So,

Mass of nitric acid = $\frac {68}{100}\times 322.34\ g$ = 219.1912 g

Molar mass of nitric acid = 63.01 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{219.1912\ g}{63.01\ g/mol}$

Moles of nitric acid = 3.4786 moles

According to the reaction,

$Cu_{(s)}+4HNO_3_{(aq)}\rightarrow Cu(NO_3)_2_{(aq)} + 2NO_2_{(g)} + 2H_2O_{(l)}$

1 mole of copper react with 4 moles of nitric acid

Thus,

0.6817 moles of copper react with 4*0.6817 moles of nitric acid

Moles of nitric acid required = 2.7268 moles

Available moles of nitric acid = 3.4786 moles

Limiting reagent is the one which is present in small amount. Thus, nitric acid is present in large amount, copper is the limiting reagent.

The formation of the product is governed by the limiting reagent. So,

1 mole of copper on reaction forms 2 moles of nitrogen dioxide

So,

0.6817 mole of copper on reaction forms 2*0.6817 moles of nitrogen dioxide

Moles of nitrogen dioxide = 1.3634 moles

Given:

Pressure = 724 torr

The conversion of P(torr) to P(atm) is shown below:

$P(torr)=\frac {1}{760}\times P(atm)$

So,

Pressure = 724 / 760 atm = 0.9526 atm

Temperature = 28.2 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T₁ = (28.2 + 273.15) K = 301.35 K

Using ideal gas equation as:

PV=nRT

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

0.9526 atm × V = 1.3634 mol × 0.0821 L.atm/K.mol × 301.35 K

⇒V = 35.41 L

3 0

3 years ago

Read the given chemical reaction. C2H6 + O2 → CO2 + H2O How many moles of O2 are required to react completely with 3.2 moles of

Vesnalui [34]

<h2>Hello!</h2>

The answer is: 11,2 moles of O2

First, we need to balance the equation in order to calculate how many moles reacts,

The balanced equation is:

$2 C2H6 + 7 O2 = 4 CO2 + 6 H2O$

So, from the equation we have that 2 moles of C2H6 reacts with 7 moles of O2, knowing that we can calculate how many moles of O2 are required to react completely with 3.2 moles of C2H6:

$3,2moles(C2H6)*\frac{7 moles (O2)}{2moles(C2H6)} =11,2 moles(O2)$

So, we need 11,2 moles of O2 to react completely with 3,2 moles of C2H6.

Have a nice day!

3 0

3 years ago

Write a balanced net ionic equation showing only the particles involved in the reaction and balancing the charges.Pb(s) AgNO3aq)

Alexus [3.1K]

Answer:

Pb(s) + 2Ag+(aq) → 2Ag(s) + Pb2+(aq)

Explanation:

Step 1: The unbalanced equation

Pb(s) + AgNO3aq) → Ag(s) + Pb(NO3)2(aq)

Step 2: Balancing the equation

Pb(s) + AgNO3aq) → Ag(s) + Pb(NO3)2(aq)

On the right side we have 2x NO3, on the left side we have 1x NO3.

To balance the amount of NO3 on both sides, we have to multiply AgNO3 (on the left side) by 2.

Pb(s) + 2AgNO3aq) → Ag(s) + Pb(NO3)2(aq)

On the left side we have 2x Ag, on the right side we have 1x Ag.

To balance the amount of Ag on both sides, we have to multiply Ag (on the right side) by 2. Now the equation is balanced.

Pb(s) + 2AgNO3(aq) → 2Ag(s) + Pb(NO3)2(aq)

The net ionic equation, for which spectator ions are omitted - remember that spectator ions are those ions located on both sides of the equation - will look like this

Pb(s) + 2Ag+(aq) → 2Ag(s) + Pb2+

8 0

4 years ago