<u>Answer:</u> The mass of gallium produced by the electrolysis is 0.0354 grams.
<u>Explanation:</u>
The equation for the deposition of Ga(s) from Ga(III) solution follows:

- To calculate the total charge, we use the equation:

where,
C = charge
I = current = 0.490 A
t = time required (in seconds) =
(Conversion factor: 1 min = 60 s)
Putting values in above equation, we get:

- To calculate the moles of electrons, we use the equation:

where,
C = charge = 147 C
F = Faradays constant = 96500

- Now, to calculate the moles of gallium, we use the equation:

where,
n = number of electrons transferred = 3
Putting values in above equation, we get:

- To calculate the mass of gallium, we use the equation:

Moles of Gallium = 
Molar mass of Gallium = 69.72 g/mol
Putting values in above equation, we get:

Hence, the mass of gallium produced by the electrolysis is 0.0354 grams.
Answer:
3.46 x 10²⁴ molecules.
Explanation:
- <em>Knowing that every one mole of a substance contains Avogadro's no. of molecules (NA = 6.022 x 10²³).</em>
<em><u>Using cross multiplication:</u></em>
1.0 mole of HBr → 6.022 x 10²³ molecules.
5.75 mole of HBr → ??? molecules.
∴ The no. of molecules of HBr are in 5.75 mol = (6.022 x 10²³ molecules) ( 5.75 mole) / (1.0 mol) = 3.46 x 10²⁴ molecules.