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3 years ago

Write a balanced equation for the reaction of sulfuric acid (H,SO) and

Chemistry

1 answer:

Sonbull [250]3 years ago

3 0

Answer:

Explanation:

Word equation:

sulfuric acid + ammonium hydroxide → ammonium sulfate + water

Chemical equation:

H₂SO₄ + NH₄OH → (NH₄)₂SO₄ + H₂O

Balanced chemical equation:

H₂SO₄ + 2NH₄OH → (NH₄)₂SO₄ + 2H₂O

The given reaction is the reaction of acid with base. When acid and base react salt and water are produced. In given reaction an acid sulfuric acid and base ammonium hydroxide react and form ammonium sulfate salt and water. The given reaction also follow the law of conservation of mass.

Steps to balance the equation:

Steps 1;

H₂SO₄ + NH₄OH → (NH₄)₂SO₄ + H₂O

H = 7 H = 10

S = 1 S = 1

O = 5 O = 5

N = 1 N = 2

Step 2:

H₂SO₄ + 2NH₄OH → (NH₄)₂SO₄ + H₂O

H = 12 H = 10

S = 1 S = 1

O = 6 O = 5

N = 2 N = 2

Step 3:

H₂SO₄ + 2NH₄OH → (NH₄)₂SO₄ + 2H₂O

H = 12 H = 12

S = 1 S = 1

O = 6 O = 6

N = 2 N = 2

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3 years ago

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3 years ago

Which of the following is the correct wedge and dash conformation for the following Newman projection?

kakasveta [241]

We have that the correct wedge and dash conformation for the following Newman projection is

From the Diagrams above

Two CH_3 groups points on opposite sides in plane

Two Br are on same side of plane

Two H also on same side of the plane so the plausible structure is IV

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2 years ago

Nitrogen monoxide and hydrogen react to form nitrogen and water, like this: 2NO+2 H2(g)-N29)+2H2O(9) Write the pressure equilibr

lara31 [8.8K]

Answer:

Partial pressure N₂ . (Partial pressure H₂O)² / (Partial pressure H₂)² . (Partial pressure NO)² = Kp

Explanation:

The reaction is:

2NO + 2H₂ → N₂ + 2H₂O

The expression for Kp (pressure equilibrium constant) would be:

Partial pressure N₂ . (Partial pressure H₂O)² / (Partial pressure H₂)² . (Partial pressure NO)²

There is another expression for Kp, where you work with Kc (equilibrium constant)

Kp = Kc (R.T)^Δn

where R is the Ideal Gases constant

T° is absolute temperature

Δn = moles of gases formed - moles of gases, I had initially

4 0

3 years ago

An aqueous CsCl solution is 8.00 wt% CsCl and has a density of 1.0643 g/mL at 20°C. What is the boiling point of this solution?

umka2103 [35]

<u>Answer:</u> The boiling point of solution is 100.53

<u>Explanation:</u>

We are given:

8.00 wt % of CsCl

This means that 8.00 grams of CsCl is present in 100 grams of solution

Mass of solvent = (100 - 8) g = 92 grams

The equation used to calculate elevation in boiling point follows:

$\Delta T_b=\text{Boiling point of solution}-\text{Boiling point of pure solution}$

To calculate the elevation in boiling point, we use the equation:

$\Delta T_b=iK_bm$

Or,

$\text{Boiling point of solution}-\text{Boiling point of pure solution}=i\times K_b\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}$

where,

Boiling point of pure solution = 100°C

i = Vant hoff factor = 2 (For CsCl)

$K_b$ = molal boiling point elevation constant = 0.51°C/m

$m_{solute}$ = Given mass of solute (CsCl) = 8.00 g

$M_{solute}$ = Molar mass of solute (CsCl) = 168.4 g/mol

$W_{solvent}$ = Mass of solvent (water) = 92 g

Putting values in above equation, we get:

$\text{Boiling point of solution}-100=2\times 0.51^oC/m\times \frac{8.00\times 1000}{168.4g/mol\times 92}\\\\\text{Boiling point of solution}=100.53^oC$

Hence, the boiling point of solution is 100.53

6 0

3 years ago