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vlabodo [156]
3 years ago
6

Write a balanced equation for the reaction of sulfuric acid (H,SO) and

Chemistry
1 answer:
Sonbull [250]3 years ago
3 0

Answer:

Explanation:

Word equation:

sulfuric acid + ammonium hydroxide  →  ammonium sulfate + water

Chemical equation:

H₂SO₄ + NH₄OH → (NH₄)₂SO₄ + H₂O

Balanced chemical equation:

H₂SO₄ + 2NH₄OH → (NH₄)₂SO₄ + 2H₂O

The given reaction is the reaction of acid with base. When acid and base react salt and water are produced. In given reaction an acid sulfuric acid and base ammonium hydroxide react and form ammonium sulfate salt and water. The given reaction also follow the law of conservation of mass.

Steps to balance the equation:

Steps 1;

H₂SO₄ + NH₄OH → (NH₄)₂SO₄ + H₂O

H = 7                            H = 10

S = 1                             S = 1

O = 5                           O = 5

N = 1                            N = 2

Step 2:

H₂SO₄ + 2NH₄OH → (NH₄)₂SO₄ + H₂O

H = 12                            H = 10

S = 1                             S = 1

O = 6                           O = 5

N = 2                           N = 2

Step 3:

H₂SO₄ + 2NH₄OH → (NH₄)₂SO₄ + 2H₂O

H = 12                            H = 12

S = 1                               S = 1

O = 6                             O = 6

N = 2                             N = 2

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KonstantinChe [14]

Answer:

m_{Cr_2O_3}^{actual}=62.4gCr_2O_3

Explanation:

Hello!

In this case, according to the reaction:

4Cr+3O_2\rightarrow 2Cr_2O_3

We can see there is a 4:2 mole ratio between chromium and chromium (III) oxide, this, for the given 56.2 g of chromium, the theoretical yield of the oxide product is computed down below:

m_{Cr_2O_3}^{theoretical}=56.2gCr*\frac{1molCr}{52.0gCr}*\frac{2molCr_2O_3}{4molCr} *\frac{151.99gCr_2O_3}{1molCr_2O_3}  =82.13gCr_2O_3

Now, considering the 76.0-% yield for this reaction, the actual yield turns out:

m_{Cr_2O_3}^{actual}=82.13gCr_2O_3*\frac{76.0gCr_2O_3}{100gCr_2O_3} \\\\m_{Cr_2O_3}^{actual}=62.4gCr_2O_3

Best regards!

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Explanation:

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