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4 years ago

Balanced equation for beta decay of iodine-138

Chemistry

1 answer:

Andreyy894 years ago

7 0

Answer:

Explanation:

Please take a look at the attached picture about the general formula of beta decay and the answer.

beta decay is an atom breaking down into a new atom of another element which the atomic number is 1 larger than the original, and one electron (β particle). The mass no. of the new atom remains same as before.

138 is iodine's mass number, the atomic number of iodine is 53, referred from a periodic table. The new atom formed will be Xe, which has an atomic no. of 54.

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4 years ago

For 100.0 mL of a solution that is 0.040M CH3COOH and 0.010 M CH3COO, what would be the pH after adding 10.0 mL 50.0 mM HCl?

damaskus [11]

Answer:

The pH of the buffer is 3.90

Explanation:

The mixture of a weak acid CH3COOH and its conjugate base CH3COO produce a buffer that follows the equation:

pH = pKa + log [A-] / [HA]

Where pH is the pH of the buffer, pKa is the pKa of acetic acid (4.75), and [A-] could be taken as the moles of the conjugate base and [HA] the moles of thw weak acid.

To solve this question we need to find the moles of the CH3COOH and CH3COO- after the reaction with HCl:

CH3COO- + HCl → CH3COOH + Cl-

The moles of CH3COO- are its initial moles - the moles of HCl added

And moles of CH3COOH are its initial moles + moles HCl added

Moles CH3COO-:

Initial moles = 0.100L * (0.010mol / L) = 0.00100moles

Moles HCl = 0.010L * (0.050mol / L) = 0.000500 moles

Moles CH3COO- = 0.000500 moles

Moles CH3COOH:

Initial moles = 0.100L * (0.040mol / L) = 0.00400moles

Moles HCl = 0.010L * (0.050mol / L) = 0.000500 moles

Moles CH3COO- = 0.003500 moles

pH is:

pH = 4.75 + log [0.000500] / [0.00350]

pH = 3.90

<h3>The pH of the buffer is 3.90</h3>

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3 years ago

True or false: The force exerted onto an object must be perpendicular to the displacement if work is to be considered done.

RUDIKE [14]

Answer:

its letter B. false

Explanation:

bjchakfbhc

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3 years ago