These are the nonvascular plants or bryophytes (mosses, liverworts, and hornworts), the seedless vascular plants (clubmosses and ferns including, horsetails, club mosses, and whisk ferns), gymnosperms (conifers, cycads, Ginkgo, and gnetophytes), and angiosperms, or flowering plants.

4 0

1 year ago

which of the functions have a range of real numbers greater than or equal to 1 or less than or equal to-1

lilavasa [31]

The question is incomplete. Here is the complete question:

Which of the functions have a range of all real numbers greater than or equal to 1 or less than or equal to -1? check all that apply.

A. $y=\sec x$

B. $y= \tan x$

C. $y= \cot x$

D. $y= \csc x$

Answer:

A. $y=\sec x$

D. $y=\csc x$

Step-by-step explanation:

Given:

The range is greater than or equal to 1 or less than or equal to -1.

The given choices are:

Choice A: $y=\sec x$

We know that, the $\sec x=\frac{1}{\cos x}$

The range of $\cos x$ is from -1 to 1 given as [-1, 1]. So,

$|\cos x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\cos x|}\geq 1\\|\sec x|\geq 1$

Therefore, on removing the absolute sign, we rewrite the secant function as:

$\sec x\leq -1\ or\ \sec x\geq 1\\$

Therefore, the range of $y=\sec x$ is all real numbers greater than or equal to 1 or less than or equal to-1.

Choice B: $y= \tan x$

We know that, the range of tangent function is all real numbers. So, choice B is incorrect.

Choice C: $y= \cot x$

We know that, the range of cotangent function is all real numbers. So, choice C is incorrect.

Choice D: $y=\csc x$

We know that, the $\csc x=\frac{1}{\sin x}$

The range of $\sin x$ is from -1 to 1 given as [-1, 1]. So,

$|\sin x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\sin x|}\geq 1\\|\csc x|\geq 1$

Therefore, on removing the absolute sign, we rewrite the cosecant function as:

$\csc x\leq -1\ or\ \csc x\geq 1\\$

Therefore, the range of $y=\csc x$ is all real numbers greater than or equal to 1 or less than or equal to-1.

6 0

3 years ago

4.3*(-3.2)*0 positive or negative or zero Help

iragen [17]

I think it's 0 since anything multiplied by 0 is, well, 0! No matter what the sign is. I believe the correct answer is 0 :)

4 0

3 years ago

Read 2 more answers

Help meeeeeeee please :(.

vodomira [7]

Answer:

$x^{3} -5x^{2} -6x +8 \frac{-2}{x + 3}$

Step-by-step explanation:

$x^{3} -5x^{2} -6x +8 \frac{-2}{x + 3}$

x + 3 / $x^{4} - 2x^{3}-21x^{2} -10x +22$

-( $x^{4} + 3x^{3}$ )

- $5x^{3} -21x^{2} -10x +22$

-( $-5x^{3} -15x^{2}$ )

$-6x^{2} -10x +22$

-( $-6x^{2} -18x$ )

8x +22

-(8x + 24)

$\frac{-2}{x + 3}$

4 0

3 years ago