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Leona [35]
3 years ago
13

A scientist makes a boric acid (H3BO3) solution by dissolving 22.5 g of H3BO3 in water to make 750.0 mL of solution. Calculate t

he number of moles of H3BO3 present:
Chemistry
2 answers:
antiseptic1488 [7]3 years ago
8 0

Answer:

A = 22.5

B = 61.83

C = 0.364

D = 750.0

E = 0.485

Explanation:

GaryK [48]3 years ago
6 0

Answer:

The correct answer is 0.36 mol

Explanation:

First we have to calculate the molecular weight (Mw) of H₃BO₃ from the molar masses of the elements:

Mw(H₃BO₃)= 3 x Molar mass H + Molar mass B + (3 x Molar mass O)

                  = 3 x 1 g/mol + 10.8 g/mol + (3 x 16 g/mol)

                  = 61.8 g/mol

The molecular weight indicates that there are 61.6 grams per mol of substance. The scientist has 22.5 g, thus we can calculate the number of moles of H₃BO₃ by dividing the mass into the molecular weight as follows:

Number of moles of H₃BO₃ = mass/Mw= (22.5 g)/(61.8 g/mol) = 0.36 mol

There are 0.36 mol of H₃BO₃ in 750.0 mL of solution.

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Answer : The percentage composition of carbon, hydrogen and sulfur in a compound is, 38.8 %, 9.6 % and 51.6 % respectively.

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