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ryzh [129]
3 years ago
12

When does the composition of a substance does not change?

Chemistry
1 answer:
blagie [28]3 years ago
4 0
I think when it does not react with anything I think
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How many atoms are in 64 g sulfur (S)?
Katen [24]

Answer:

there are 6.022*1023 atoms

Explanation:

32 g S * (1 mole S/32 g S) * (6.022*1023 atoms/1 mole S)= 6.022*1023 atoms

6 0
3 years ago
Read 2 more answers
How many ions in 6.41 moles of K2O? Please show work.
Oksana_A [137]
1. Convert the number of moles to number of particles (divide 6.41 by 6.022 x 10^23)

2. K2O dissociates into three ions (2 potassium ions and 1 oxide ion), so multiply the result from step 1 by 3 to get your answer
4 0
3 years ago
When the reaction
yaroslaw [1]
We can express the rate equation in this form:
-r = k A^n B^m

where -r is the rate
k is the rate constant,
A is the concentration of CH3Cl
n is the order with respect to CH3Cl
B is the concentration of H2O
m is the order with respect to H2O

We can solve this by trial and error or by calculus. The first method is easier. The rate constant does not depend on the concentration of the reactant. Assume values of n and m and solve for k in each experiment. The only option that gives really close values of k in each experiment is:
<span>C. CH3Cl: firstorder H2O: second order
</span>
3 0
3 years ago
Cesium sulfite is formed from the cs cation and the so2−3 anion. What is the correct formula for this compound?
Anna35 [415]

Cesium Sulfite is formed from the Cs cation and the SO₃⁻² anion. The correct formula for this compound is Cs₂SO₃.

<h3>What is Cation ? </h3>

Cations are positively charged ions. It forms when an element lose one or more electrons.

<h3>
What is Anion ? </h3>

Anions are negatively charged ions. It form when an element gains one or more electrons.

Symbol         Cs⁺¹         SO₃⁻²

Valency           +1              -2

Formula of the compound is Cs₂SO₃.

Thus from the above conclusion we can say that Cesium Sulfite is formed from the Cs cation and the SO₃⁻² anion. The correct formula for this compound is Cs₂SO₃.

Learn more about the Cation and Anions here: brainly.com/question/20005547
#SPJ1

3 0
1 year ago
Calculate the concentration of each species in a 0.240 m c6h5nh3cl solution.
amm1812
The solution for this problem is:
C6H5NH3Cl is a strong salt: C6H5NH3+ + Cl- C6H5NH3+ + H2O <-----> C6H5NH2 + H3O+ 
K = Kw/ Kb= 1.0 x 10^-14 / 3.8 x 10^-10= 2.6 x 10^-5 

=2.6 x 10^-5 = x^2 / 0.240-x 
x = [H3O+] = 0.00251 M 
pH = 2.60 is the concentration
8 0
3 years ago
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