In a balanced chemical reaction, the number of moles that are present at the side of the reactant must be always equal to the side of product formation this is known as a balanced chemical equation.

The balanced chemical reaction will be 6Li + N₂ → 2Li₃N.

Here 6 moles of lithium is reacting with one nitrogen but as it is in gaseous state it is N₂ after reacting with lithium it will give two moles

Therefore, balanced equation will be 6Li + N₂ → 2Li₃N

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6 0

2 years ago

What is the name of the element with a valence electron configuration of 4s24p3?

Gnesinka [82]

<span>The element Arsenic, or As in the periodic table, possesses the valence electron configuration of 4s2 4p3. It has an atomic number of 33 and an atomic mass of 74.92, and is classified as a metalloid.</span>

4 0

4 years ago

How many grams of sodium chromate, Na2CrO4, are needed to react completely with

JulsSmile [24]

Answer:

We need 27.0 grams of Na2CrO4 to react with 56.7 grams of AgNO3

Explanation:

Step 1: data given

Mass of silver nitrate AgNO3 = 56.7 grams

Molar mass AgNO3 = 169.87 g/mol

Molar mass of Na2CrO4 = 161.97 g/mol

Step 2: The balanced equation

2AgNO3 + Na2CrO4 → Ag2CrO4 + 2NaNO3

Step 3: Calculate moles AgNO3

Moles AgNO3 = mass AgNO3 / molar mass AgNO3

Moles AgNO3 = 56.7 grams / 169.87 g/mol

Moles AgNO3 = 0.334 moles

Step 4: Calculate moles Na2CrO4 moles needed

For 2 moles AgNO3 we need 1 mol Na2CrO4 to produce 1 mol Ag2CrO4 and 2 moles NaNO3

For 0.334 moles AgNO3 we need 0.334 / 2 = 0.167 moles Na2CrO4

Step 5: Calculate mass Na2CrO4

Mass Na2CrO4 = 0.167 moles * 161.97 g/mol

Mass Na2CrO4 = 27.0 grams

We need 27.0 grams of Na2CrO4 to react with 56.7 grams of AgNO3

8 0

3 years ago