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alukav5142 [94]
3 years ago
13

What is the volume of the cylinder? Express the answer in terms of .

Mathematics
2 answers:
Inga [223]3 years ago
6 0

Answer:

v=904.78 cm3

Step-by-step explanation:

the volume of the cylinder is 904.78 cm3.

d=8

h=18

solution :

v=pi(d/2)2 h =pi x (8/2)2 x 18

v=904.77868 cm3

malfutka [58]3 years ago
5 0

Answer:

I think it is 3619.11 your welcome

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If you measure a tds of 1.4%, and you used a brew ratio of 15, what is the percent extraction?
sweet-ann [11.9K]
Answer: the extraction is 18.2%.

Explanation:

Let's see few definitions:
TDS = Total Dissolved Solids = solids dissolved in the brew
PE = Percent Extraction = percent of solids extracted from the dry coffee grounds

The percent extraction can be calculated by the formula:
PE = TDS × Rm

where
Rm = ratio between the mass of the brew and the mass of dry grounds

Now, you need to consider the following facts:
1) every 1g of coffee absorbs 2g of water
2) the given brew ratio is 1:15, which means that for every 1g of grounds we use 15g of water

Let's call
x = grams of coffee grounds we want to use
Therefore the mass of the brew will be: 
m(brew) = water we use - water absorbed by the coffee
              = 15·x - 2·x
              = 13·x

Therefore,
Rm = m(brew) / x
       = 13·x / x
       = 13

Hence, the percent of extraction will be:
PE = <span> TDS × Rm
      = 1.4 </span>× 13
      = 18.2
4 0
3 years ago
Suppose the point (x, y) is translated vertically d units <br><br> Plzz help me with this
Elina [12.6K]
Is there supposed to be an attached image for us to see?
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Can it be concluded that if there is a 50% chance of contracting a communicable disease through contact with an infected person,
crimeas [40]

Answer:

No it cannot be concluded.

Step-by-step explanation:

The probability of getting the disease in the first attempt is 50%

The probability of getting the disease in the second attempt is 50%

Thus the probability of getting the disease in either of the turns is 50%+50%=100% (which may seem to be true)

BUT

The probability of not  getting the disease in the first attempt is 50%

The probability of not getting the disease in the second attempt is 50%

Thus the probability of not getting the disease in either of the turns is 50%+50%=100% (which is also true for this case)

Thus the probability of getting the disease in either of the 2 contacts is still 50%

4 0
3 years ago
A drawer contains 12 brown socks and 12 black socks, all unmatched. A man takes socks out at random in the dark. 21. Required in
avanturin [10]

Answer:

6  socks

Step-by-step explanation:

What we must do is calculate the probability of this happening, that he takes out two black socks in the first two taken out.

There are 12 black socks and in total they are 24, therefore the probability of drawing 1 is:

12/24

and now the probability of getting another one is 11 (there is one less outside) and in total they are 23:

11/23

the final probability is the multiplication of these events:

(12/24) * (11/23)

P = 0.24

Now, to know how many you should get, we multiply the probability by the total number of socks, that is:

0.24 * 24 = 5.76

So you must take out at least 6 socks for the above to happen.

6 0
4 years ago
20 points Return to questionItem 4Item 4 20 points Police records in the town of Saratoga show that 13 percent of the drivers st
Sladkaya [172]

Answer:

a) 0.1423

b) 0.2977

c) 0.56

Step-by-step explanation:

For each driver stopped for speeding, there are only two possible outcomes. Either they have invalid licenses, or they do not. The probability of a driver having an invalid license is independent from other drivers. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

13 percent of the drivers stopped for speeding have invalid licenses.

This means that p = 0.13

14 drivers are stopped

This means that n = 14

(a) None will have an invalid license.

This is P(X = 0)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{14,0}.(0.13)^{0}.(0.87)^{14} = 0.1423

(b) Exactly one will have an invalid license.

This is P(X = 1)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{14,1}.(0.13)^{1}.(0.87)^{13} = 0.2977

(c) At least 2 will have invalid licenses.

Either less than 2 have invalid licenses, or at least 2 does. The sum of the probabilities of these events is decimal 1. Mathematically, this is

P(X < 2) + P(X \geq 2) = 1

We want P(X \geq 2)

So

P(X \geq 2) = 1 - P(X < 2)

In which

P(X < 2) = P(X = 0) + P(X = 1) = 0.1423 + 0.2977 = 0.44

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.44 = 0.56

8 0
3 years ago
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