Wavelength is 6.976 x 10^ -35 m
Explanation:
In this, we can use De Broglie’s equation. This equation is the relationship between De Broglie’s wavelength, velocity and the mass of a moving object. In this equation, we are using plank's constant which is 6.626 x 10^-34 m^2 kg/s.
We know that one mile per hour is equivalent to 0.447 M/S.
And One gram is equivalent to 10^-3 kg.
De Broglie’s wavelength = λ ( wave length) = Plank’s constant/ Mass x velocity
λ ( wave length) = 6.626 x 10^ -34/ (425 x10^-3) x ( 50 x 0.447)
= 6.626 x 10^ -34/ 0. 425 x 22.35
= 6.626 x 10^ -34/ 9.498
= 6.976 x10^ -35 m
So, the wavelength of the football will be 6.976 x 10^ -35 m
I would have to say the answer is a. True.
Answer is: Ksp for calcium sulfate is 2.36·10⁻⁴.
Balanced chemical reaction (dissociation):
CaSO₄(s) → Ba²⁺(aq) + SO₄²⁻(aq).
m(CaSO₄) = 0.209 g.
n(CaSO₄) = m(CaSO₄) ÷ M(CaSO₄).
n(CaSO₄) = 0.209 g ÷ 136.14 g/mol.
n(CaSO₄) = 0.00153 mol.
s(CaSO₄) = n(CaSO₄) ÷ V(CaSO₄).
s(CaSO₄) = 0.00153 mol ÷ 0.1 L = 0.0153 M.
Ksp = [Ca²⁺] · [SO₄²⁻].
[Ca²⁺] = [SO₄²⁻] = s(CaSO₄).
Ksp = (0.0153 M)² = 2.36·10⁻⁴.
Protons, the number of protons cannot change or the element will change as well.
