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Alex787 [66]
2 years ago
14

SOICHIOMETRY HOW MANY MOL OF NITROGEN DIOXIDE ARE REQUIRED TO PRODUCE 2.75 MOL NITRIC ACID? 3NO2+ H20→ 2HNO3+ NO

Chemistry
1 answer:
pishuonlain [190]2 years ago
4 0

Answer: C

Explanation: Hope this help :D

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concentrated phosphoric acid is90% H3PO4 by mass and the remaining mass is water. The molarity of H3PO4 is 12.2M at temperature
blondinia [14]

Answer:

82.0 mL

Explanation:

Step 1: Given data

  • Concentration of concentrated acid (C₁): 12.2 M
  • Volume of concentrated acid (V₁): ?
  • Concentration of dilute acid (C₂): 1.00 M
  • Volume of dilute acid (V₂): 1.00 L

Step 2: Calculate the required volume of the concentrated acid

We want to prepare a dilute solution from a concentrated one. We can calculate the volume of the concentrated acid using the dilution rule.

C₁ × V₁ = C₂ × V₂

V₁ = C₂ × V₂ / C₁

V₁ = 1.00 M × 1.00 L / 12.2 M = 0.0820 L = 82.0 mL

4 0
2 years ago
How many people have died as a results of the spread of virus?
pshichka [43]

Answer:

70000000000

Explanation:

6 0
3 years ago
In order to calculate the number of neutrons you must subtract the what from the what?​
Katyanochek1 [597]

Answer:

You take the atomic, or proton number of the element, and you subtract it from the element's mass number.

6 0
3 years ago
Read 2 more answers
How much energy is evolved during the formation of 197 g of Fe, according to the reaction below?
hoa [83]

Answer:

ΔH for formation of 197g Fe⁰ = 1.503 x 10³ Kj => Answer choice 'B'

Explanation:

Given Fe₂O₃(s) + 2Al⁰(s) => Al₂O₃(s) + 2Fe⁰(s) + 852Kj

197g Fe⁰ = (197g/55.85g/mol) = 3.527 mol Fe⁰(s)

From balanced standard equation 2 moles Fe⁰(s) => 852Kj, then ...

3.527 mole yield (a higher mole value) => (3.527/2) x 852Kj = 1,503Kj (a higher enthalpy value).

______

NOTE => If 2 moles Fe gives 852Kj (exo) as specified in equation, then a <u>higher energy value</u> would result if the moles of Fe⁰(s) is <u>higher than 2 moles</u>. The ratio of 3.638/2 will increase the listed equation heat value to a larger number because 197g Fe⁰(s) contains more than 2 moles of Fe⁰(s) => 3.527 mole Fe(s) in 197g.  Had the problem asked for the heat loss from <u>less than two moles Fe⁰(s)</u> - say 100g Fe⁰(s) (=1.79mole Fe⁰(s)) - then one would use the fractional ratio (1.79/2) to reduce the enthalpy value less than 852Kj.  

8 0
2 years ago
Which of the following is NOT true about nuclear fusion?
inysia [295]

<u>Answer:</u>

I think it's (C)

The products are suitable for making nuclear weapons.

hope this helps!

6 0
3 years ago
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