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Alexxx [7]
3 years ago
12

A single ion channel is selectively permeable to K+ and has a resistance of 1.0 GΩ. During an experiment the channel is open for

approximately 1.0 ms while the voltage across the channel is maintained at +80.0 mV with a patch clamp. How many K+ ions travel through the channel?
Physics
1 answer:
IrinaVladis [17]3 years ago
3 0

Answer:

5.0 × 10⁵

Explanation:

Quantity of charge Q = It

V= IR

I = V / R

Q = Vt/R

Q = ne

ne = Vt/R

n, number of K⁺ ions = Vt / Re

V = 80 × 10 ⁻³

t = 1 × 10⁻³ s

R = 1  × 10⁹ Ω

e = 1.6 × 10⁻¹⁶C

n, number of K⁺ ions = (80 × 10 ⁻³ V ×  1 × 10⁻³ s ) / (1  × 10⁹ Ω ×  1.6 × 10⁻¹⁹C) = 5.0 × 10⁵

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A 4000 N force acts on an object that initially has a momentum of 400 kg-m/s for 0.9 seconds. What is the final momentum of the
kaheart [24]

Answer:

4360 Kgm/s

Explanation:

Applying,

Ft = M-M'................. Equation 1

Where F = force, t = time, M = Final momentum, M' = Initial momentum.

make M the subject of the equation

M = Ft+M'............ Equation 2

From the question,

Given: F = 4000 N, t = 0.9 seconds, M' = 400 kg-m/s

Substitute these values into equation 2

M = 4000+(0.9×400)

M = 4000+360

M = 4360 kgm/s

Hence the final momentum is 4360 kgm/s

3 0
3 years ago
Some hummingbirds beat their wings more than 50 times per second. A scientist is measuring the time it takes for a hummingbird t
Aliun [14]

Answer:

millisecond

Explanation:

Time is measured in seconds in the SI system. The scientist will measure the time it takes to complete one flap of the wings. In the SI system the use of prefix makes it easier to describe the value. It is as follows

1\ ns=10^{-9}\ s

1\ \mu s=10^{-6}\ s

1\ ms=10^{-3}\ s

1\ cs=10^{-2}\ s

Here, the wings flap so fast that the millisecond should be used.

5 0
3 years ago
Three wires meet at a junction. wire 1 has a current of 0.40 aa into the junction. the current of wire 2 is 0.73 aa out of the j
Mnenie [13.5K]

The magnitude of the current in wire 3 is (I₃)= 0.33A

<h3>How to calculate the value of the magnitude of the current in wire 3 ?</h3>

To calculate the magnitude of the current in wire 3 we are using the Kirchhoff’s current law,

I₁ + I₂ + I₃ = 0

Where we are given,

I₁ = current in wire 1

=0.40 A.

I₂ = current in wire 2

= -0.73 A.

We have to calculate the magnitude of the current in wire 3, I₃

Now we put the known values in above equation, we get,

I₁ + I₂ + I₃ = 0

Or, I₃ = -.(I₁ + I₂)

Or, I₃ = -.(0.40 - 0.73)

Or, I₃ = 0.33 A

From the above calculation, we can conclude that the current in wire 3 is  I₃ = 0.33 A

Learn more about current:

brainly.com/question/25537936

#SPJ4

7 0
1 year ago
1.What is an object that appears fuzzy through a material that is?
Anna007 [38]

Answer:

not sure 5

but thaks for the points

7 0
3 years ago
Calculate the quantity of heat absorbed by 50 g of water that warms from 30∘C to 90∘C.
natima [27]

Answer:

12,558 J

Explanation:

The amount of heat absorbed by the water is given by:

Q=mC_S \Delta T

where

m = 50 g is the mass of the water

C_s = 4.186 J/gC is the water specific heat

\Delta T=90C-30C=60^{\circ}C is the temperature increase of the water

Substituting into the formula, we find

Q=(50.0 g)(4.186 J/gC)(60^{\circ}C)=12,558 J

5 0
4 years ago
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