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4 years ago

according to many anthropologists a land brigade during the ice age allowing between which two countries

Physics

2 answers:

Jet001 [13]4 years ago

5 0

Continents: North America and Asia
Countries: Canada and Siberia, or Alaska (United States) and Siberia

ioda4 years ago

4 0

Well first of all, I think you're referring to the theory of the land "bridge",
not 'brigade'.

The main problem with this question is that during the Ice Age,
there were no countries, so there are no names to answer with.

The suspected land bridge spanned the expanse of open water
that would come to be called the 'Bering Strait' millions of years
later, after the bridge was long gone. Its ends would have been
located on land in different parts of what would come to be known
as Mother Russia far in the future. And even later, after another
couple hundred years, one of those ends would cease to be part
of Russia and would become part of the USA. But as I said earlier,
during the time that the land bridge existed, there were no countries.

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Consider 3 polarizers. Polarizer 1 has a vertical transmission axis and polarizer 3 has a horizontal transmission axis. Taken to

kirill [66]

Answer:

Option D.) 0.09 I₀

Explanation:

The intensity, I, of a polarized light after passing through a polarizing filter is given by $I = I_{0} cos^{2} \theta$

$I_{0} =$ Original Intensity

$\theta =$ Angle between the direction of polarization and the axis of filter

After passing through the first polarizer, the initial intensity, $I_{o}$ is halved, i.e $I_{1} = \frac{I_{0} }{2}$

After passing through the second polarizer, the angle of polarization, θ = 30⁰

$I_{2} = I_{1} cos^{2} \theta$

$I_{2} = \frac{I_{0} }{2} cos^{2} 30\\I_{2} =\frac{3}{8} I_{0} \\I_{2} = 0.375 I_{0}$

After passing through the third polarizer, the angle of polarization, θ = 90⁰-30⁰ = 60⁰

$I_{3} = I_{2} cos^{2} \theta$

$I_{3} = 0.375I_{0} cos^{2} 60$

$I_{2} =0.09 I_{0}$

7 0

4 years ago

A 1,500 kg car’s speed changes from 30 m/s to 15 m/s after the brakes are applied. Calculate the work done onto the car from the

HACTEHA [7]

The work done onto the car is 506,250 J

The work done on a system implies an increase in the internal energy of the system as a result of some forces acting on the system from the outside.

From the parameters given:

The mass of the car = 1500 kg
The initial speed = 30 m/s
The final speed = 15 m/s

The work done onto the car refers to the change in the kinetic energy (i.e. ΔK.E)

$\mathbf{=\dfrac{1}{2} mv_1^2 -\dfrac{1}{2} mv_2^2}$

$\mathbf{=\dfrac{1}{2} m(v_1^2 - v_2^2)}$

$\mathbf{=\dfrac{1}{2} \times 1500 \times (30^2 - 15^2)}$

= 506,250 J

Therefore, we can conclude that the work done on the car is 506,250 J

Learn more about work done here:

brainly.com/question/18762601

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3 years ago

Calculate the kinetic energy of a moving 4 kg object traveling at a velocity of 3 m/a

Alina [70]

Answer:

Explanation:KE = 18 J

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3 years ago

A 10-g bullet moving horizontally with a speed of 2.0 km/s strikes and passes through a 4.0-kg block moving with a speed of 4.2

SVEN [57.7K]

Answer:

$K=512J$

Explanation:

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