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3 years ago

Plzhelpppppp pros only helppppppp me plzzzzzzzzzzz ill reporte you if you do bad qweshtones

Mathematics

1 answer:

forsale [732]3 years ago

8 0

Answer:

Step-by-step explanation:

$8x^3+12x=\\4(2x^3+3x)=\\4x(2x^2+3)$

Therefore, the correct answer is D. Hope this helps!

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What is 4/5 * 7/9. Ik It’s easy but I don’t feel like doing it ;)

valina [46]

Answer:

28/45

Step-by-step explanation:

Dont worry i also don't feel like doing fractions most the time they can get very annoying when you have to work with a lot of them.

7 0

2 years ago

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What is the slope of the line?

Leya [2.2K]

Answer:

The slope of the line is -3

Step-by-step explanation:

I chose the points (-2,3) and (0,-3)

The slope formula: m= $\frac{y_2-y_1}{x_2-x_1}$

$\frac{-3-3}{0-(-2)}$ ==> $\frac{-3-3}{0+2}$ ==> $\frac{-6}{2}$ = $-3$

Our final answer is -3.

Hope that helps!

5 0

2 years ago

Which expression is equivalent to (2x + 7x*) - (5x² - 4x)?

Westkost [7]

Answer:

5x^2 + 13x

Step-by-step explanation:

3 0

2 years ago

Carlos performed a transformation on trapezoid EFGH to create E′F′G′H′, as shown in the figure below:

Nataliya [291]

Answer:

90° clockwise rotation or 270° anticlockwise rotation

Step-by-step explanation:

(x,y)=(y,-x)

E(-6,-4)=E'(-4,6)

F(-4,-4)=F'(-4,4)

G(-2,-6)=G'(-6,2)

H(-7,-7)=H'(-7,7)

Therefore, E prime is (-4,6), F prime is (-4,4), G prime is (-6,2) and H prime is (-7,7).

4 0

1 year ago

What is the value of i 97 – i? –i 0 –2i i Superscript 96

Valentin [98]

The question is not clearly readable, but I'm assuming the expression which makes more sense, so you can have a clue

Answer:

$i^{97}-i=0$

Step-by-step explanation:

Powers of The Imaginary Unit

The imaginary unit i is defined as

$i=\sqrt{-1}$

The first powers of i are

$i^0=1$

$i^1=i$

$i^2=(\sqrt{-1})^2=-1$

$i^3=i.i^2=-i$

$i^4=i^2.i^2=1$

And so on the cycle repeats every four numbers. To find the value of $i^{96}$ we can find the remainder of 96/4=0. So $i^{96}=i^0=1$

The given expression is

$i^{97}-i$

Factoring

$i(i^{96}-1)$

Since $i^{96}=1$

$=i(1-1)=0$

The required value is 0

6 0

3 years ago

Read 2 more answers