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viktelen [127]
3 years ago
9

28 points!! please help

Physics
1 answer:
kobusy [5.1K]3 years ago
8 0
7(a) transpiration is faster in warmer dry air
(b)(I)xylem
(ii) 1. They are stacked end-to-end
2. Consists of dead cells
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What type of sound is produced when string vibrates rapidly?
amid [387]
The faster a string vibrates, the higher frequency sound it produces,
and the higher the pitch is that we hear. 
8 0
3 years ago
Consider two planets of mass m and 2m,
Rzqust [24]

Answer:

Part a)

\frac{F_1}{F_2} = 10.125

Part b)

\frac{v_1}{v_2} = \sqrt{\frac{4.5r}{r}} = 2.12

Part c)

\frac{T_1}{T_2} = 9.54

Explanation:

Part a)

As we know that the gravitational force is given as

F = \frac{GMm}{r^2}

so we will have to find the ratio of force on two planets due to star

so here we have

\frac{F_1}{F_2} = \frac{m_1r_2^2}{m_2r_1^2}

\frac{F_1}{F_2} = \frac{m (4.5r)^2}{(2m) r}

\frac{F_1}{F_2} = 10.125

Part b)

Orbital speed is given as

v = \sqrt{\frac{GM}{r}}

so the ratio of two orbital speed is given as

\frac{v_1}{v_2} = \frac{r_2}{r_1}

\frac{v_1}{v_2} = \sqrt{\frac{4.5r}{r}} = 2.12

Part c)

Time period is given as

T = 2\pi\sqrt{\frac{r^3}{GM}}

so the ratio of two time period is given as

\frac{T_1}{T_2} = \sqrt{\frac{r_1^3}{r_2^3}}

\frac{T_1}{T_2} = \sqrt{\frac{4.5r^3}{r^3}}

\frac{T_1}{T_2} = 9.54

8 0
3 years ago
Read 2 more answers
A 9 m3 container is filled with 300 kg of r-134a at 10°c. what is the specific enthalpy (kj/kg) of the r-134a in the container?
andreev551 [17]
Given the mass of R-134a m = 300kg; Volume of the container V = 9  cu. meter; Temperature of R-134a T = 10 degrees Celsius; 
Formula of specific volume : v = V / m = 9 / 300 = 0.03 cu. m / kg. 
At T = 10 degrees Celsius from saturated R-134a tables, vf = 0.0007930 cu. m /kg; vg = 0.049403 cu. m/kg. We know v = vf + x (vg - vf), so 0.03 = 0.0007930 + x (0.049403 - 0.0007930), which makes x = 0.601.  
Specific enthalpy of R-134a in the container is h = hf + x*hfg = 65.43 + (0.601 * 190.73). Answer is 180.0587 kJ/kg
8 0
3 years ago
In a rainstorm with a strong wind, what determines the best position in which to hold an umbrella?
AVprozaik [17]

Answer:

It is best to hold the umbrella at an angle which is parallel to the direction of rain drops.

Explanation:

Velocity of vector of rain drops plays crucial role here. Direction of the wind causes the rain drop directions. Hence handle of the umbrella should be parallel to the direction of rain drops. there will be more umbrella area if we keep umbrella in the direction.

3 0
3 years ago
Read 2 more answers
A change in position of an object is its:
finlep [7]

Answer:

it's B I think I did this the other day tbh sorry if it's wrong btw hope this helps

8 0
3 years ago
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