3 years ago

Calculate the wavelength of a wave if 5 complete waves occupy a length of 20m

Physics

1 answer:

Nezavi [6.7K]3 years ago

6 0

The answer is 20 / 5 = 4

You might be interested in

What happens to light as it moves at an angle from a medium that has an

ki77a [65]

Answer:

Explanation:

i went to school like you

8 0

3 years ago

Read 2 more answers

How to find the acceleration of on object at a slope

vredina [299]

Answer:

i need free points sry

Explanation:

8 0

3 years ago

Read 2 more answers

11. (2 pts) A photon with energy 44.8 eV is absorbed by a hydrogen atom in its ground state, knocking the

Vikentia [17]

Answer: 3.3·10^6 m/s

Explanation: Ionization energy of H is 13.6 eV. So the kinetic energy of electron is 31,2 eV. Kinetic Energy of Electron is E = ½mv^2

1 eV = 1.60·10^-19 J and m = 9.1·10^-31 kg. Solving speed v = √( 2E / m)

v = √(2·31.2·1.60·10^-19 J /9.1·10^-31 kg) = 3.3·10^6 m/s

5 0

3 years ago

Barometers have long been used to predict the weather. Jay and Jeff were responsible for recording the class weather data each d

AfilCa [17]

Answer:

Explanation:

You would have rain. You would have clouds, precipitation, and strong winds.

4 0

3 years ago

Read 2 more answers

A certain region currently has wind farms capable of generating a total of 2200 megawatts (2.2 gigawatts) of power. Complete p

Alla [95]

Answer:

$E=7.708\times 10^9\ KW-hr$

n=770,880.

Explanation:

Given that

P= 2200 MW

Power of wind farm = 0.4 or 40%

So the power produce by wind farm = 0.4 x P

P'=0.4 x 2200 MW

P'=880 MW

P'=880,000 KW

We know that

1 year = 365 days

1 day = 24 hr

1 year = 365 x 24 hr

1 year = 8760

So the energy produce in one year

E= 8760 x P'

E= 8760 x 880,000 KW

$E=7.708\times 10^9\ KW-hr$

Given that average house hold use 10,000 KW-hr

So lets take total n number of house hold use power

E= n x 10,1000

$7.708\times 10^9= n \times 10000$

n=770,880.

8 0

3 years ago