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adoni [48]
3 years ago
7

Which statement explains the relationship between corresponding

Mathematics
1 answer:
Galina-37 [17]3 years ago
7 0

Answer:

Each term in pattern Y is 3 times the corresponding term in pattern X.

Step-by-step explanation:

Given the information:

X - 0, 5, 10, 15, 20

Y - 0, 15, 30, 45, 60

We can use deduce from physical observation of the data that each term in pattern Y is 3 times the corresponding term in pattern X.

However, to establish our relationship, we can plot the linear relationship and generate the equation of the line.

Thus gives us :

Y = 3X + 0

Which means for every pattern in Y, it is 3 times the corresponding pattern in X

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The measure of angle STV is 160.
ratelena [41]

Answer:

x = 125

Step-by-step explanation:

x = 160 - 35

x = 125

4 0
3 years ago
What is the value of x in the figure shown below?
satela [25.4K]

50?

I'm assuming 50 because the angles to a triangle always adds up to 180 and this one has 130 and 130+50=180

4 0
2 years ago
Use the coordinates of the plotted points to complete the calculation below. Pay attention to negative signs
Alex787 [66]

answer:

-1/2

explanation

1-2 / 4-2 = -1/2

4 0
3 years ago
Read 2 more answers
Seventy percent of children who go to the doctor have fevers. Of those with fevers, 30% also have a rash. Of those without fever
Allisa [31]

Answer:

The probability that a child with a rash does not have a fever is 22%

Step-by-step explanation:

1. Probability of having fever:

P(fever)=0.70

2. Probability of not having fever:

P(not fever)=1-P(fever)\\P(not fever)=1-0.70\\P(not fever)=0.30

3. Probability of fave fevers and a rash:

P(fever and rash)=(0.70)(0.30)=0.21

4. Probability of having a rash but not a fever:

P(rash and not fever)=(0.30)(0.20)=0.60

5. Probability of having a rash:

P(rash)=P(rash and fever)+P(rash and no fever)\\P(rash)=0.21+0.06=0.27

6. Probability a child with a rash does not have a fever

P=\frac{P(rash and not fever)}{P(rash)} =\frac{0.06}{0.27} =0.22

22% of the child at the doctor's office with a rash does not have a fever.

5 0
3 years ago
At a math competition 2 students can answer 40 questions in 1 hour. At the same rate, how many questions could 5 students answer
const2013 [10]

Answer:

25 questions

Step-by-step explanation:

At a math competition 2 students can answer 40 questions in 1 hour.

Therefore, 1 student can answer in 1 hour =  \frac{40}{2}

                                                                     = 20 questions

5 students can answer in 1 hour = 20 × 5 = 100 questions

60 minutes = 1 hour

15 minutes =  \frac{15}{60} = 0.25 hours

5 students can answer in 0.25 hours = 100 × 0.25

                                                              = 25 questions

5 students could answer 25 questions in 15 minutes.

6 0
3 years ago
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