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Over [174]
3 years ago
10

PLZ HELP Organisms on earth are ________ based life forms. - oxygen - hydrogen - carbon

Chemistry
2 answers:
Bess [88]3 years ago
5 0

Answer:

Carbon based life forms

Artyom0805 [142]3 years ago
4 0

Answer:

carbon based on life forms

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How many different atoms are there in H2SO4?
Alenkinab [10]
7, i'm pretty sure, hope I helped!
8 0
3 years ago
Put the following in the correct chronological order from what happened first to what happened last.
Scilla [17]

Answer:

2-3-1-4

Explanation:

The astronomer Nicolaus Copernicus did not have a theory about the Earth revolving around the sun until he got into astronomy and began to study the patterns of the sun and the moon as well as reading other entries from previous astronomers. You can pretty much guess from there, he had to have the theory before proving it etc.  

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2 years ago
Why is large-scale nuclear fission a rare phenomenon on Earth? A. There isn't enough energy to start a chain reaction in nature.
siniylev [52]

The answer is; C

The radioisotopes in the interior of the earth are not in pure form and have many embedded impurities and are interspersed. Therefore when a neutron is released by a decaying atom, its chances of hitting another radioisotope atom (to continue the chain reaction) are lower than in a manmade nuclear reactor. This way, the radioactive chain reaction in the earth’s interior is not well sustained.


6 0
3 years ago
Read 2 more answers
Do Alkali Metal Compounds form precipitates? And Why?
Alexeev081 [22]

Answer:

Alkali metal hydroxides can be used to test the identity of metals in certain salts. The colour of the precipitate will help identify the metal : Calcium hydroxide is soluble; no precipitate is formed.

6 0
2 years ago
Consider the reaction below.
Law Incorporation [45]

Answer:

  • <u>First choice: 0.042</u>

Explanation:

Given decomposition reaction:

  • 1PCl₅ (g) ⇄ 1PCl₃ + 1Cl₂(g)

Equilibrium constant:

  • K_{eq}=\frac{[PCl_3]^1[Cl_2]^1}{[PCl_5]^1}

Stoichiometric coefficients and powers equal to 1 are not usually shown as they are understood, but I included them in order to shwow you how they intervene in the equilibrium expressions: each concentration is raised to a power equal to the respective stoichiometric coefficient in the equilibrium equation.

So, your calculations are:

K_{eq}=\frac{(0.020M)(0.020M)}{0.0095M}=0.042M

6 0
3 years ago
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