A Neutralisation reaction, the alkali is neutralizing the acid.
Answer:
0.092 %
Explanation:
The equation of the reaction can be computed as :
recall that; the number of moles = 
By applying the method of enthalpy of combustion for sucrose at the same time changing the time from hours to seconds, we can determine the total energy output.
i.e
Given that the sun supplies about 1.0 kilowatt, to KJ/m² s, we have:
Finally, the percentage of sunlight used to produce sucrose :
= 
= 0.092 %
Answer: pH of HCl =5, HNO3 = 1,
NaOH = 9, KOH = 12
Explanation:
pH = -log [H+ ]
1. 1.0 x 10^-5 M HCl
pH = - log (1.0 x 10^-5)
= 5 - log 1 = 5
2. 0.1 M HNO3
pH = - log (1.0 x 10 ^ -1)
pH = 1 - log 1 = 1
3. 1.0 x 10^-5 NaOH
pOH = - log (1.0 x 10^-5)
pOH = 5 - log 1 = 5
pH + pOH = 14
Therefore , pH = 14 - 5 = 9
4. 0.01 M KOH
pOH = - log ( 1.0 x 10^ -2)
= 2 - log 1 = 2
pH + pOH = 14
Therefore, pH = 14 - 2 = 12
Answer:
Explanation:
I would ask him why would he want to add the blue stripe?
Answer:
cant you just ask your teacher?
but other wise i might be able to help but not in this kind of way just plz leave a comment if you have something to say before deleting this answer
