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JulijaS [17]
2 years ago
11

A random sample of 121 bottles of cologne showed an average content of 4 ounces. It is known that the standard deviation of the

contents (i.e., of the population) is 0.22 ounces. In this problem the 0.22 is Group of answer choices the standard error of the mean a parameter the average content of colognes in the long run a statistic
Mathematics
1 answer:
pychu [463]2 years ago
5 0

Answer:

Standard error of the mean parameter the average content of colognes

                                S.E = 0.02 ounces                            

Step-by-step explanation:

<u><em>Explanation</em></u><em>:-</em>

<em>Size of random sample 'n' = 121 bottles</em>

<em>mean of the sample </em>x^{-} = 4 ounces

<em>Standard deviation of Population</em>

<em>                       σ = 0.22</em>

<em>Standard error of the mean parameter the average content of colognes</em>

<em>                              </em>S.E = \frac{S.D}{\sqrt{n} }<em></em>

<em>                              </em>S.E = \frac{S.D}{\sqrt{n} } = \frac{0.22}{\sqrt{121} }<em></em>

                             S.E = 0.02

<u><em>Final answer:-</em></u>

<em> Standard error of the mean parameter the average content of colognes</em>

<em>                S.E = 0.02 ounces                            </em>

<em></em>

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Answer:

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Step-by-step explanation:

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N=\frac{k}{C}

Now given N = 480 and C = 4.90, we first find k:

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Now, as second step, we need this time to find N, when

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Note, we know know k = 2352, so we find N:

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Remark

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m = - 1/6

================

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===============

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