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Volgvan
3 years ago
9

Solve for x. (x - 3)2 = 64

Mathematics
2 answers:
Gala2k [10]3 years ago
8 0

Answer:

X= 35

Step-by-step explanation:

2x-6=64

2x=64+6

2x=70

X=35

Jlenok [28]3 years ago
5 0

Answer: x=35

Step-by-step explanation:

(x-3) x 2 =64

2x-6=64

2x=64+6

2x=70

Divide both sides of the equation by 2 which gives you the answer x=35

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Use set-builder notation to describe the following sets: (a) {1,2,3,4,5,6,7} (b) {1, 10, 100, 1000, 10000} (c) {1,1/2, 1/3, 1/4,
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Answer:

A) The set builder notation is: {n | n∈Z, 1≤n≤7}.

B) The set builder notation is: \{10^x | x=0,1,2,3,4\}

C) The set builder notation is: \{\frac{1}{n} | n\in z\}

D) The set builder notation can be: \{x\ \in R | x=x^3\ and\ x\neq 1\}

Step-by-step explanation:

Consider the provided information,

We need to use set-builder notation to describe the following sets.

(a) {1,2,3,4,5,6,7}

Here, the number are integer starting from 1 to 7.

Thus, the set builder notation is: {n | n∈Z, 1≤n≤7}.

(b) {1, 10, 100, 1000, 10000}

The above set can be written as:

\{1, 10, 100, 1000, 10000\}=\{10^0, 10^1, 10^2, 10^3, 10^4\}

Thus, the set builder notation is: \{10^x | x=0,1,2,3,4\}

(c) {1, 1/2, 1/3, 1/4, 1/5, ...}

Here the numerator is 1 for each term but denominator is natural number.

Thus, the set builder notation is: \{\frac{1}{n} | n\in z\}

(d) {0}

The set builder notation can be: \{x\ \in R | x=x^3\ and\ x\neq 1\}

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