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Phoenix [80]
2 years ago
14

How many moles are in 150 g of Iron (III) oxide? (Fe203)

Chemistry
2 answers:
artcher [175]2 years ago
8 0

Answer:

The answer is 159.6882

ollegr [7]2 years ago
6 0

Answer:

0.939moles

Explanation:

no. of moles = mass/molar mass

= 150/159.7

= 0.939moles

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Three blocks are shown: Three blocks are shown. Block A has mass 3 kilograms, length 6 centimeters, height 4 centimeters, and wi
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Answer:

Block A has the greatest density.

Explanation:

Three blocks are shown: Three blocks are shown.

Block A has mass 3 kilograms, length 6 centimeters, height 4 centimeters, and width 2 centimeters.

Block B has mass 1 kilograms, length 6 centimeters, height 2 centimeters, and width 4 centimeters.

Block C has mass 2 kilograms, length 2 centimeters, height 6 centimeters, and width 4 centimeters.

Which statement is correct?

- Block A has the greatest density.

- Block B has the greatest density.

- The density of Block A is equal to the density of Block B.

- The density of Block B is equal to the density of Block C

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Gas pressure is caused by
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It's a rapid motion and collisions of molecules with the walls of the container that causes pressure.

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Answer:

Ice is the last major agent of weathering, erosion, and deposition.

Explanation:

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Read 2 more answers
1 C3H8 + 5 O2 --> 3 CO2 + 4H20. If 1.5 moles of C3H8 react, how many
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Answer:

First confirm the reaction is balanced:

C3H8 + 5O2 --> 3CO2 + 4H20 (3 cabon - check; 8 hydrogen - check; 10 oxygen - check).

a) In the equation there is a 5:1 ratio between propane and oxygen.  We also know that number of mole is proportional to pressure and volume.  Since pressure is constant (STP) then the volume of O2 is 7.2 * 5 = 36 litres.

b) For a near ideal gas that PV = nRT (combined gas law).  So for 7.2 litres propane we find n(propane) = 101.3 * 7.2/8.314*298 ~ 0.29 mole (using metric units throughout for simplicity).

There is a 1:3 ratio between propane and CO2.  Therefore 3 * 0.29 = 0.87 mole of CO2 is produced.

MW(CO2) ~ 44 g/mol.  Therefore m(CO2) = 44 * 0.87 ~ 38.3 g

c) We know we need more oxygen than propane (due to the 1:5 ratio) so oxygen is the limiting reagent.  Again Volume is proportional to number of mole and we see there is a 5:4 ratio between oxygen and water.  Therefore the volume of water vapour produced will be (4/5) * 15 = 12 litres.

The other questions use the same technique and will give you some much needed practice.

Explanation:

7 0
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