Answer:
1.46mol of Al2(SO4)3 weights 499.5 grams
Explanation:
First we will find the gram formula mass of Al2(SO4)3.
Al * 2 = 26.98 g/mol * 2 = 53.96 g
SO4 * 3 = 96.06 g/mol * 3 = 288.18
53.96 + 288.18 = 342.14 g
That is the mass of 1 mol of AL2(SO4)3.
Now we will multiply 342.14g by 1.46.
342.14 * 1.46 = 499.5244 g
Or ... 499.5 g
Answer:
<u>49.54 g</u>
Explanation:
Let's take the masses of both calcium sulfate and sulfur dioxide formed.
Sulfur dioxide = 32 + 2(16) = <u>64 g</u>
Calcium sulfate = 40 + 32 + 4(16) = <u>136 g</u>
So, under ideal conditions, to produce 136 g of Calcium sulfate, we require 64 g of Sulfur dioxide.
But, it mentions the process is only 95% efficient.
Hence, taking the ratio :
x = <u>49.54 g</u> (approximately)
Answer:
yes
Explanation:
the polyatomic ion is acetate, C2H3O2