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3 years ago

HELP ASAP!!! The potential energy of a 25 kg bicycle resting at the top of a 3 m high hill is __ J.

Physics

1 answer:

Nataly_w [17]3 years ago

7 0

Answer:

PE = 735 J

Explanation:

PE = mgh:

PE = (25)(9.8)(3) = 735 J

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A 15.0-mW laser puts out a narrow beam 2.00 mm indiameter.

UkoKoshka [18]

Explanation:

It is known that formula for energy per unit area per unit time is as follows.

S = $\frac{P}{A}$

= $\frac{P}{\pi \times r^{2}} = \frac{4P}{\pi d^{2}}$

$c \epsilon_{o} E^{2} = \frac{4P}{\pi d^{2}}$

E = $\sqrt{\frac{4P}{\pi d^{2} c \epsilon_{o}}}$

Now, putting the values we will calculate the electric field as follows.

E = $\sqrt{\frac{4P}{\pi d^{2} c \epsilon_{o}}}$

= $\sqrt{\frac{4 \times 15 \times 10^{-3} W}{3.14 \times (2mm \times \frac{1m}{1000 mm})^{2} \times 3 \times 10^{8} \times 8.85 \times 10^{-12}}}$

= 1341.03 V/m

Now, we will calculate the average magnetic field as follows.

B = $\frac{E}{c}$

= $\frac{1341.03 V/m}{3 \times 10^{8} m/s}$

= $4.47 \times 10^{-6}$ T

= $4.47 \mu T$

Thus, we can conclude that the average (rms) value of the magnetic field is $4.47 \mu T$ .

3 0

3 years ago

A 3rd harmonic is being produced in a tube that is open at both ends. The tube is 3 meters long and

attashe74 [19]

The frequency of the second harmonic is 880 Hz (a pitch of A5). The speed of sound through the pipe is 350 m/sec. Find the frequency of the first harmonic and the length of the pipe. The length of an air column is related mathematically to the wavelength of the wave which resonates within it.

4 0

3 years ago

The frequency of the harmonics following a fairly simple pattern, as described in the text. If the frequency of the fundamental

zalisa [80]

Answer:

f2 = 140 Hz

Explanation:

let fundamental frequency is f1 = 70.0 Hz

formula for finding the higher frequency when fundamental frequency is known

fn = n f1 (where f1 is fundamental frequency and n = 1,2,3,4,5...........)

for the second frequency n=2

f2 = 2 × 70.0 Hz