Answer:
<em><u>60 m/s</u></em>
Explanation:
Average Speed = Distance/ Time
= 15/0.25 = 60m/s
Answer:
The second option: 11 kg * m/s
Explanation:
Recall that linear momentum is defined as the product of the mass times its velocity, therefore in this case, the mass is 0.45 kg , and the speed is 25 m/s, therefore the linear momentum is:
P = m * v = 0.45 Kg * 25 m/s = 11.25 kg * m/s
So roundng the answer to the nearest whole number, you get 11 kg * m/s, which is the second option they give you.
Answer:
The value is
Explanation:
From the question we are told that
The volume is
The initial pressure is
The initial temperature is
The final temperature is
Generally for an adiabatic process the workdone is mathematically represented as
Here is the internal energy of the system which is mathematically represented as
So
Generally from ideal gas equation we have that
Here R is the gas constant with value
So
=>
So
=>
Below are the answers:
a. There is a constant magnetic Feld, which means B is constant, so we can rewrite the change in fux as above.Because ΔA is positive, there will be a negative emf in the loop, corresponding to an induced magnetic momentpointing to the left on the page. The current in the loop will be into the page at the top and out of the page at<span>the bottom
</span>V=-Δφ/ Δt = -B·ΔA/ Δ<span>t
b. </span>As the loop’s radius is increasing, we can think about individual electrons in the wire loop as moving radially<span>outward. We’ll consider one in the top of the loop (which is moving up the page). Using the Lorentz ²orce Law
</span>F=q(~v⇥~B)=qvB(ˆy⇥ˆx)=-qvB<span>ˆ
</span>Constant forces pointing into the center of the loop will result in circular orbits (around the wire). Because the<span>force is pointing into the center of the loop, we know we have positive current at that point (into the page).</span>
The force on one end of the trough is 5.4 X 10⁵ N
<u>Explanation:</u>
The triangle is equilateral which means all the interior angles are 60° and the sides are 6m long.
According to the figure,
AI / 8 = sin (60) = √3/2
AI = 4√3
The depth of the water is AI = 4√3
The interval becomes, | 0 , 4√3|
w = 2JK
(the hydrostatic force acting on the strip is the product of the pressure and the area)
where.
ρ = 875 kg/m³
g = 9.8m/s²
d = depth ( d = y')
limit is 0 → 4√3
On solving the equation, we get the value of limit as 32√3
Therefore, the force on one end of the trough is 5.4 X 10⁵ N