Answer:
the answer is b. b velocity. remember v=v
Answer:
(a) 106 kPa
(b) 0.0377 mol
(c) 17.8 cm
Explanation:
(a) There are three forces on the piston. Atmospheric pressure pushing down, weight pulling down, and pressure of the gas pushing up.
∑F = ma
PA − mg − PₐA = 0
P = (PₐA + mg) / A
P = Pₐ + (mg / A)
P = 101,300 Pa + (40.0 N) / (π (0.05 m²))
P = 106,393 Pa
P = 106 kPa
(b) Use ideal gas law.
PV = nRT
(106,393 Pa) (π (0.05 m²) (0.11 m)) = n (8.314 Pa m³/mol/K) (20 + 273.15) K
n = 0.0377 mol
(c) Use ideal gas law to find the new volume of the gas.
PV = nRT
(106,393 Pa) (π (0.05 m²) h) = (0.0377 mol) (8.314 Pa m³/mol/K) (200 + 273.15) K
h = 0.178 m
h = 17.8 cm
Answer:
E=3 x 10^4 N/c
Explanation:
The electric field strength can be found out disk with a uniform positive surface charge density by
σ= charge density
r= radius of the disk
z= position in which we have to find electric field = 15 cm
ε_0= constant ( vacuum permitivity)
putting values we get
solving we get
E=30000 N/c
E=3 x 10^4 N/c
<span>6.7 x 10-11....Have a good day with a big fat A+
</span>
Answer:
The amount of work that must be done to compress the gas 11 times less than its initial pressure is 909.091 J
Explanation:
The given variables are
Work done = 550 J
Volume change = V₂ - V₁ = -0.5V₁
Thus the product of pressure and volume change = work done by gas, thus
P × -0.5V₁ = 500 J
Hence -PV₁ = 1000 J
also P₁/V₁ = P₂/V₂ but V₂ = 0.5V₁ Therefore P₁/V₁ = P₂/0.5V₁ or P₁ = 2P₂
Also to compress the gas by a factor of 11 we have
P (V₂ - V₁) = P×(V₁/11 -V₁) = P(11V₁ - V₁)/11 = P×-10V₁/11 = -PV₁×10/11 = 1000 J ×10/11 = 909.091 J of work
