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3 years ago

Find the area of a circle with a radius of 2.

Mathematics

2 answers:

ipn [44]3 years ago

6 0

Answer:

the answer is 4(pi)

Step-by-step explanation:

ruslelena [56]3 years ago

5 0

Answer:

A =12.56 units^2

Step-by-step explanation:

The area of a circle is found by

A = pi r^2

We know the radius is 2

A = pi (2)^2

A = 4pi

Using 3.14 as pi

A = 4(3.14)

A =12.56 units^2

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Byron bought 1.9 of banannas and 11/12 pounds of grapes. how many more pounds of bananas did he buy

Genrish500 [490]

Answer:

11/12

Step-by-step explanation:

I took 1.9 and turned it into a fraction and the fraction is 1 9/12 so if you have 11/12 and 1 9/12 then you bought 10/12 more pounds of banana than grapes

5 0

3 years ago

Evaluate the expression for x = 15. X - 5 =

soldier1979 [14.2K]

Steps to solve:

x - 5 for x = 15

~Substitute

15 - 5

~Subtract

Best of Luck!

4 0

3 years ago

Read 2 more answers

Can someone pls help me . ASAPPP

STALIN [3.7K]

Volume without holes = 3 x 6 x 11 = 198 cubic inches.

Calculate volume of one hole:

3.14 x 0.5^2 x 3 = 2.355 cubic inches

There are 3 holes: 3 x 2.355 = 7.065

Subtract volume of the holes from the brick:

198 - 7.065 = 190.935 cubic inches.

Rounded to the nearest tenth: 190.9 cubic inches.

8 0

3 years ago

Read 2 more answers

A. f(x) = l-2xl - 3 Domain: {1, 2, 3} Find the range

gizmo_the_mogwai [7]

Hello there!

We are given the function:

$\displaystyle \large{ f(x) = | - 2x| - 3} \\$

To find the range, we know that domain is the set of all x-values and also called 'input' while range is the set of all y-values and also called 'output'.

Basic Function - you add the input, you get the output. You add x-value in a function, you get y-value. You add domain, you get range.

So, we substitute x = 1,2 and 3 in the function.

x = 1

$\displaystyle \large{ f(1) = | - 2(1)| - 3} \\ \displaystyle \large{ f(1) = | - 2| - 3} \\$

Recall that any numbers in absolute value are always positive.

$\displaystyle \large{ f(1) = 2 - 3} \\ \displaystyle \large{ f(1) = - 1} \\$

x = 2

$\displaystyle \large{ f(2) = | - 2(2)| - 3} \\ \displaystyle \large{ f(2) = | - 4 | - 3} \\ \displaystyle \large{ f(2) = 4 - 3} \\ \displaystyle \large{ f(2) = 1}$

x = 3

$\displaystyle \large{ f(3) = | - 2(3)| - 3} \\ \displaystyle \large{ f(3) = | - 6| - 3} \\ \displaystyle \large{ f(3) = 6 - 3} \\ \displaystyle \large{ f(3) = 3}$

Therefore, Range: {-1,1,3}

Let me know if you have any questions!

Topic: Absolute Value Function / Modulus Function

6 0

3 years ago

3.2 km is equivalent to which of the following? You may choose more than one correct answer

stiks02 [169]

Options 2, 4, 6 are correct.

8 0

3 years ago

Read 2 more answers