(a) 5^31-5^29 = 5^29(5^2-1)
= 5^29(24)
= 5^29(6)(4)
=5^26(6)*[(5)(5)(4)]
=5^26(6)*100
(b) 25^9+5^17 = 5^18+5^17
=5^17(5+1)
=5^17(6)
=5^16[(5)(6)]
=5^16*30
(c) 27^10–9^14 = 3^30-3^28
=3^28(3^2 -1)
=3^28(8)
=3^27[(3)(8)]
=3^27*24
Answer:
x=1
Step-by-step explanation:
Answer:
n=601
Step-by-step explanation:
A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".
The margin of error is the range of values below and above the sample statistic in a confidence interval.
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The population proportion have the following distribution
In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by and . And the critical value would be given by:
The confidence interval for the mean is given by the following formula:
The margin of error for the proportion interval is given by this formula:
(a)
And on this case we have that and we are interested in order to find the value of n, if we solve n from equation (a) we got:
(b)
Since we don't have a prior estimation for the proportion we can use 0.5 as estimation. And replacing into equation (b) the values from part a we got:
And rounded up we have that n=601
If each bird had two wings, there would be 4016 wings. For each two-winged bird we replace with a four-winged bird, the total number of wings would increase by 2. We need 22 more wings, so 11 two-winged birds need to be replaced by four-winged birds. Thus, there are 1997 two-winged and 11 four winged birds.
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