3 years ago

HELP ASAP WILL MARK BRAINLIEST

Mathematics

1 answer:

nydimaria [60]3 years ago

8 0

Answer:

4000 + .06x ≥ 7000

Step-by-step explanation:

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On a lunch counter, there are 3 oranges, 5 apples, and 2 bananas. If 3 pieces of fruit are selected, find the probability that 1

muminat

Answer:

$Probability = \frac{1}{24}$

Step-by-step explanation:

Given

$Oranges = 3$

$Apples = 5$

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Required

Determine the probability of 1 orange, 1 apple and 1 banana

Since, order is not important:

$Probability = P(Orange) * P(Apple) * P(Banana)$

$Probability = \frac{3}{10} * \frac{5}{9} * \frac{2}{8}$

<em>The difference in the numerator is as a result of picking the fruit without replacement</em>

$Probability = \frac{30}{720}$

$Probability = \frac{1}{24}$

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