now, if we take 2000 to be the 100%, what is 2200? well, 2200 is just 100% + 10%, namely 110%, and if we change that percent format to a decimal, we simply divide it by 100, thus 
.
so, 1.1 is the decimal number we multiply a term to get the next term, namely 1.1 is the common ratio.
![\bf \qquad \qquad \textit{sum of a finite geometric sequence}\\\\S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad \begin{cases}n=n^{th}\ term\\a_1=\textit{first term's value}\\r=\textit{common ratio}\\----------\\a_1=2000\\r=1.1\\n=4\end{cases}\\\\\\S_4=2000\left[ \cfrac{1-(1.1)^4}{1-1.1} \right]\implies S_4=2000\left(\cfrac{-0.4641}{-0.1} \right)\\\\\\S_4=2000(4.641)\implies S_4=9282](https://tex.z-dn.net/?f=%20%5Cbf%20%5Cqquad%20%5Cqquad%20%5Ctextit%7Bsum%20of%20a%20finite%20geometric%20sequence%7D%5C%5C%5C%5CS_n%3D%5Csum%5Climits_%7Bi%3D1%7D%5E%7Bn%7D%5C%20a_1%5Ccdot%20r%5E%7Bi-1%7D%5Cimplies%20S_n%3Da_1%5Cleft%28%20%5Ccfrac%7B1-r%5En%7D%7B1-r%7D%20%5Cright%29%5Cquad%20%5Cbegin%7Bcases%7Dn%3Dn%5E%7Bth%7D%5C%20term%5C%5Ca_1%3D%5Ctextit%7Bfirst%20term%27s%20value%7D%5C%5Cr%3D%5Ctextit%7Bcommon%20ratio%7D%5C%5C----------%5C%5Ca_1%3D2000%5C%5Cr%3D1.1%5C%5Cn%3D4%5Cend%7Bcases%7D%5C%5C%5C%5C%5C%5CS_4%3D2000%5Cleft%5B%20%5Ccfrac%7B1-%281.1%29%5E4%7D%7B1-1.1%7D%20%5Cright%5D%5Cimplies%20S_4%3D2000%5Cleft%28%5Ccfrac%7B-0.4641%7D%7B-0.1%7D%20%20%5Cright%29%5C%5C%5C%5C%5C%5CS_4%3D2000%284.641%29%5Cimplies%20S_4%3D9282%20)
<h3>
Answer: True</h3>
This is often how many math teachers and textbooks approach problems like this. The overlapped region is the region in which satisfies every inequality in the system. Be sure to note the boundary of each region whether you're dealing with a dashed line or a solid line. Dashed lines mean points on the boundary do not count as solution points, whereas solid boundaries allow those points as part of the solution set.
Side note: This is assuming you're dealing with 2 variable inequalities. If you only have one variable, you don't need to graph and instead could use algebra. Graphing doesn't hurt though.
Answer:
Option C
Step-by-step explanation:
It was rotated to the right
Answer:
y = -5x/4 + 0
Step-by-step explanation:
Find the slope
y = -5/4x - 4
Slope is the coefficient of x
Slope m = -5/4
Substitute m into point slope form equation
y - y1 = m(x - x1)
y - y1 = -5/4( x - x1)
Substitute the point into the equation
( 4 , -5)
x1 = 4
y1 = -5
y - y1 = -5/4( x - x1)
y - (-5) = -5/4( x - 4)
y + 5 = -5/4(x - 4)
Using a slope intercept form equation
y = mx + c
y - intercept point y
m - slope
x - intercept point x
c - intercept
open the bracket with -5/4
y + 5 = -5(x - 4)/4
y + 5 = (-5x + 20)/4
y = (-5x + 20)/4 - 5
LCM = 4
y =( -5x + 20 - 20)/4
y = ( -5x + 0)/4
Rearrange in
y = mx + c
y = -5x/ 4 + 0/4
y = -5x/4 + 0
The equation of the line is
y = -5x/4 + 0
