Answer:
Infinite solutions.
Step-by-step explanation:
If we let x = 1 then y = 3, or if x = 3 y = 5 and so on.
We can substitute any number of values of x and find the corresponding value of y so there are infinite solutions.
Lim x->1 (x^2+8x-2)
substitute x =1
= 1^2 +8(1)-2
= 1 +8 -2
= 7
So the limit = 7