Answer:
Explanation:
Given;
resonance frequency (F₀) = 700 kHz
resistor, R = 10 Ohm
bandwidth (BW) = 10 kHz
bandwidth (BW)
make L (inductor) the subject of the formula
make C (capacitor) the subject of the formula
quality factor (Q)
quality factor (Q) = 69.99
Answer:
108.37°C
Explanation:
P₁ = Initial pressure = 101 kPa
V₁ = Initial volume = 530 m³
T₁ = Initial temperature = 10°C = 10+273.15 =283.15 K
P₂ = Final pressure = 101 kPa (because it is open to atmosphere)
V₂ = Final volume = 530 m³
P₁V₁ = n₁RT₁
⇒101×530 = n₁RT₁
⇒53530 J = n₁RT₁
P₂V₂ = n₂RT₂
⇒53530 J = n₂RT₂
Dividing the first two equations we get
∴Temperature must the air in the balloon be warmed before the balloon will lift off is 381.25-273.15 = 108.37°C
Answer:
Explanation:
As we know that if the object is placed on the inclined plane then the force of friction on the object is counterbalanced by the component of the weight of the object along the inclined plane.
So we can say
now if we increase the inclination of the plane then the component of the weight weight along the inclined plane will increase and hence the friction force will also increase.
As we know that the limiting value or the maximum value of friction force at the static condition is given by
so we have
so we will have
so now we have
so maximum possible angle of the inclined plane is